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In a doubly excited magnetic system with salient pole type stator and rotor, if the rotor is not allowed to move, then the equation for magnetic field stored energy in establishing the currents from zero to is and ir is __________
  • a)
    Wfld =1/2 is2L+ 1/2 ir2Lr
  • b)
    Wfld = 1/2 is2 Ls + Mrs is ir
  • c)
    Wfld =1/2 isLs + 1/2 ir2 Lr + Mrs is ir
  • d)
    Wfld = 1/2 ir2Lr + Mrs is ir
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a doubly excited magnetic system with salient pole type stator and ...
As the rotor is not allowed to move, dWmech = 0, thus dWelec = 0 + dWfld = is+ irr, if in this equation, we introduce the self and mutual inductance terms, (Ψ= Lsis) and integrate the resulting equation from 0 to is, 0 to ir and 0 to iris, the respective terms, finally we get Wfld = 1/2 is2Ls+ 1/2 ir2Lr + Mrs is ir.
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In a doubly excited magnetic system with salient pole type stator and ...
Doubly excited magnetic systems are commonly used in machines such as generators and motors. In these systems, both the stator and rotor have separate windings, allowing for independent control of the magnetic fields. In the given system, the stator is of the salient pole type, which means it has protruding poles that concentrate the magnetic flux.

The equation for magnetic field stored energy in establishing the currents from zero to is and ir can be derived as follows:

1. Magnetic Field Energy in Stator Winding (Wfld_stator):
The energy stored in the stator winding can be calculated using the formula:
Wfld_stator = 1/2 * is^2 * Ls,
where is is the stator current and Ls is the stator winding inductance.

2. Magnetic Field Energy in Rotor Winding (Wfld_rotor):
The energy stored in the rotor winding can be calculated using the formula:
Wfld_rotor = 1/2 * ir^2 * Lr,
where ir is the rotor current and Lr is the rotor winding inductance.

3. Magnetic Field Energy due to Mutual Inductance (Wfld_mutual):
The energy stored in the magnetic field due to the mutual inductance between the stator and rotor windings can be calculated using the formula:
Wfld_mutual = Mrs * is * ir,
where Mrs is the mutual inductance between the stator and rotor windings.

4. Total Magnetic Field Energy (Wfld_total):
The total magnetic field energy in the system is the sum of the energy in the stator winding, rotor winding, and mutual inductance:
Wfld_total = Wfld_stator + Wfld_rotor + Wfld_mutual
= 1/2 * is^2 * Ls + 1/2 * ir^2 * Lr + Mrs * is * ir.

Therefore, the correct equation for magnetic field stored energy in establishing the currents from zero to is and ir is:
Wfld = 1/2 * is^2 * Ls + 1/2 * ir^2 * Lr + Mrs * is * ir. (Option C)
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In a doubly excited magnetic system with salient pole type stator and rotor, if the rotor is not allowed to move, then the equation for magnetic field stored energy in establishing the currents from zero to is and ir is __________a)Wfld =1/2 is2Ls+ 1/2 ir2Lrb)Wfld = 1/2 is2 Ls + Mrs is irc)Wfld =1/2 is2Ls + 1/2 ir2 Lr + Mrs is ird)Wfld = 1/2 ir2Lr + Mrs is irCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In a doubly excited magnetic system with salient pole type stator and rotor, if the rotor is not allowed to move, then the equation for magnetic field stored energy in establishing the currents from zero to is and ir is __________a)Wfld =1/2 is2Ls+ 1/2 ir2Lrb)Wfld = 1/2 is2 Ls + Mrs is irc)Wfld =1/2 is2Ls + 1/2 ir2 Lr + Mrs is ird)Wfld = 1/2 ir2Lr + Mrs is irCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a doubly excited magnetic system with salient pole type stator and rotor, if the rotor is not allowed to move, then the equation for magnetic field stored energy in establishing the currents from zero to is and ir is __________a)Wfld =1/2 is2Ls+ 1/2 ir2Lrb)Wfld = 1/2 is2 Ls + Mrs is irc)Wfld =1/2 is2Ls + 1/2 ir2 Lr + Mrs is ird)Wfld = 1/2 ir2Lr + Mrs is irCorrect answer is option 'C'. Can you explain this answer?.
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