Which incorrect about alkyl bromide having molecular formula C5H11Br?a...
From the following isomers of C
5H
11Br, except IX all are capable of E2 elimination.
Which incorrect about alkyl bromide having molecular formula C5H11Br?a...
One isomer gives a single alkene on E2 elimination.
Explanation:
E2 elimination is a type of elimination reaction where a base removes a proton from a beta carbon, causing the leaving group to leave and forming a pi bond. In the case of alkyl bromides with the molecular formula C5H11Br, there are multiple isomers possible. Let's examine each option to understand why option C is correct.
a) One isomeric alkyl bromide undergoes E1 elimination at the fastest rate:
E1 elimination is a different type of elimination reaction that occurs via a two-step mechanism involving the formation of a carbocation intermediate. It does not directly apply to the given molecular formula C5H11Br, which is specifically asking about E2 elimination. Therefore, this option is incorrect.
b) Only one is incapable of reacting by the E2 mechanism:
The E2 mechanism is a bimolecular reaction where a strong base abstracts a proton from a beta carbon while the leaving group leaves. All isomers of alkyl bromide with the molecular formula C5H11Br can potentially undergo E2 elimination if the conditions are suitable. Therefore, this option is incorrect.
c) Only one isomer gives a single alkene on E2 elimination:
This option is correct. The different isomers of alkyl bromide with the molecular formula C5H11Br will have different arrangements of the alkyl groups and the bromine atom. During E2 elimination, the proton is removed from a beta carbon, and the leaving group (bromine) leaves, resulting in the formation of a pi bond. The specific arrangement of alkyl groups and the bromine atom in one isomer can lead to the formation of a single alkene product. Other isomers may result in the formation of different alkenes due to the different arrangements of substituents. Therefore, this option is correct.
d) 2-Bromopentane gives the most complex mixture of alkenes on E2 elimination:
This option is incorrect. While 2-bromopentane is one of the isomers of alkyl bromide with the molecular formula C5H11Br, it does not necessarily give the most complex mixture of alkenes on E2 elimination. The complexity of the alkene mixture depends on the specific arrangement of alkyl groups and the bromine atom in each isomer.