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For the parallel reaction A → B and A → C, of rate constants k1 and k2 respectively, both reactions of order 1, the rate expression is given as ____
  • a)
    (-rA) = k1CA + k2CA
  • b)
    (-rA) = k1CA – k2CA
  • c)
    (-rA) = k2CA
  • d)
    (-rA) = k1CA
Correct answer is option 'A'. Can you explain this answer?
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For the parallel reaction A → B and A → C, of rate constants...
For a zero order reaction,

A forms two products: B and C. The concentration of A decreases as the reaction progresses.
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For the parallel reaction A → B and A → C, of rate constants...
For a zero order reaction,

A forms two products: B and C. The concentration of A decreases as the reaction progresses.
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Community Answer
For the parallel reaction A → B and A → C, of rate constants...
+ B → C, the rate law is given by:

r = k1[A] + k2[B]

where r is the rate of reaction, k1 and k2 are rate constants, [A] and [B] are the concentrations of reactants A and B, respectively.

The overall rate of the reaction is determined by the sum of the rates of the individual reactions:

r = r1 + r2

where r1 = k1[A] and r2 = k2[B]

Therefore, the rate law for the parallel reaction A + B → C is given by:

r = k1[A] + k2[B]
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For the parallel reaction A → B and A → C, of rate constants k1 and k2 respectively, both reactions of order 1, the rate expression is given as ____a)(-rA) = k1CA + k2CAb)(-rA) = k1CA – k2CAc)(-rA) = k2CAd)(-rA) = k1CACorrect answer is option 'A'. Can you explain this answer?
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For the parallel reaction A → B and A → C, of rate constants k1 and k2 respectively, both reactions of order 1, the rate expression is given as ____a)(-rA) = k1CA + k2CAb)(-rA) = k1CA – k2CAc)(-rA) = k2CAd)(-rA) = k1CACorrect answer is option 'A'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about For the parallel reaction A → B and A → C, of rate constants k1 and k2 respectively, both reactions of order 1, the rate expression is given as ____a)(-rA) = k1CA + k2CAb)(-rA) = k1CA – k2CAc)(-rA) = k2CAd)(-rA) = k1CACorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the parallel reaction A → B and A → C, of rate constants k1 and k2 respectively, both reactions of order 1, the rate expression is given as ____a)(-rA) = k1CA + k2CAb)(-rA) = k1CA – k2CAc)(-rA) = k2CAd)(-rA) = k1CACorrect answer is option 'A'. Can you explain this answer?.
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