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If one of the diagonals of a square is along the line x = 2y and one of its vertices is A(3,0), then its side through this vertex is given by the equations:
  • a)
    y − 3x + 9 = 0,3y + x − 3 = 0
  • b)
    y + 3x + 9 = 0,3y + x − 3 = 0
  • c)
    y + 3x + 9 = 0,3y − x + 3 = 0
  • d)
    y − 3x + 3 = 0,3y + x + 9 = 0
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If one of the diagonals of a square is along the line x = 2y and one ...
As A(3, 0) does not satisfy the diagonal x = 2y.
∴ A(3,0) does not lie on the diagonal x = 2y.
Let m be the slope of a side passing through A(3, 0).
Equation of the side is: y − 0 = m(x − 3)
⇒ y = m(x − 3)...(i)
Slope of the diagonal x = 2y is 1/2.
Formula to find the angle between two lines:
Where θ is the angle between the two lines and m1 and m2 are the slope of the two lines.
Substituting m = 3, −1/3 in equation (i), we get
Hence, the correct option is (A).
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Most Upvoted Answer
If one of the diagonals of a square is along the line x = 2y and one ...
To solve this problem, we need to find the equation of the diagonal that is along the line x = 2y.

Let's assume the coordinates of the other vertex of the square are (a, b). Since the diagonal is along the line x = 2y, we can say that a = 2b.

We are given that one of the vertices is A(3, 0). Using this information, we can find the coordinates of the other vertex.

Since a = 2b, we have 3 = 2b, which gives us b = 3/2. Therefore, the coordinates of the other vertex are (a, b) = (3, 3/2).

Now, let's find the equation of the side of the square through the vertex A(3, 0) and the other vertex (3, 3/2).

The equation of a line passing through two points (x1, y1) and (x2, y2) is given by the formula:

(y - y1) = ((y2 - y1)/(x2 - x1)) * (x - x1)

Substituting the values of the points (3, 0) and (3, 3/2) into the formula, we get:

(y - 0) = ((3/2 - 0)/(3 - 3)) * (x - 3)
y = (3/2) * (x - 3)

Simplifying this equation, we get:
y = (3/2)x - (9/2)

Comparing this equation with the given options, we can see that the correct answer is option A: y - 3x + 9 = 0.
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If one of the diagonals of a square is along the line x = 2y and one of its vertices is A(3,0), then its side through this vertex is given by the equations:a)y − 3x + 9 = 0,3y + x − 3 = 0b)y + 3x + 9 = 0,3y + x − 3 = 0c)y + 3x + 9 = 0,3y − x + 3 = 0d)y − 3x + 3 = 0,3y + x + 9 = 0Correct answer is option 'A'. Can you explain this answer?
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