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Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?
- a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].
- b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]
- c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]
- d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n]...
To generate the sequence y[n] = x[3*n], you would need to iterate over the elements of x[n] and select every third element.
Here is a code example in Python:
```python
x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] # example sequence x[n]
y = [] # initialize sequence y[n]
for n in range(len(x)):
if n % 3 == 0: # select every third element
y.append(x[n])
print(y) # output: [1, 4, 7, 10]
```
In this example, the sequence x[n] is [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]. The loop iterates over each element of x[n], and if the index n is divisible by 3 (i.e. n % 3 == 0), it adds the element to the sequence y[n]. The resulting sequence y[n] is [1, 4, 7, 10].
Here is a code example in Python:
```python
x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] # example sequence x[n]
y = [] # initialize sequence y[n]
for n in range(len(x)):
if n % 3 == 0: # select every third element
y.append(x[n])
print(y) # output: [1, 4, 7, 10]
```
In this example, the sequence x[n] is [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]. The loop iterates over each element of x[n], and if the index n is divisible by 3 (i.e. n % 3 == 0), it adds the element to the sequence y[n]. The resulting sequence y[n] is [1, 4, 7, 10].
Community Answer
Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n]...
In option 1,
z1[n] = x[n - 3]
z2[n] = z1[4n] = x[4n - 3]
y[n] = z2[-n] = x[-4n - 3] ≠ x[3 - 4n]
In option 2,
z1[n] = x[n + 3]
z2[n] =z1[4n] = x[4n + 3]
y[n] = z2[-n] = x[-4n + 3]
In option 3,
v1[n] = x[4n]
v2[n] = v1[-n] = x[-4n]
y[n] = v2[n+3] = x[-4(n + 3)] ≠ x[3 - 4n]
In option 4,
v1[n] = x[n]
x2[n] = v1[-n] = x[-4n]
y[n] = v2[n-3] = x[-4(n - 3)] ≠ x[3 - 4n]
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Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer?
Question Description
Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer?.
Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer?.
Solutions for Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
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Here you can find the meaning of Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Given a sequence x[n], to generate the sequence y[n] = x[3 – 4n], which one of the following procedures would be correct?a)First delay x(n) by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and than finally time reverse z2[n] to obtain y[n].b)advance x[n] by 3 samples to generate z1[n], then pick every 4th sample of z1[n] to generate z2[n], and then finally time reverse z2[n] to obtain y[n]c)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and then finally advance v2[n] by 3 samples to obtain y[n]d)First pick every fourth sample of x[n] to generate v1[n], time-reverse v1[n] to obtain v2[n], and finally delay v2[n] by 3 samples to obtain y[n]Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
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