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Dipole moment of CH3-CH2-Cl > CH2=CH-Cl.
- a)True
- b)False
Correct answer is option 'A'. Can you explain this answer?
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Dipole moment of CH3-CH2-Cl > CH2=CH-Cl.a)Trueb)FalseCorrect answer...
The dipole moment of CH3-CH2-Cl can be calculated by considering the polarity and bond lengths of the molecule.
The molecule has a polar covalent bond between the carbon and chlorine atoms, with the chlorine atom being more electronegative than the carbon atom. This results in a partial negative charge on the chlorine atom and a partial positive charge on the carbon atom.
In addition, the C-C and C-H bonds are also polar due to the difference in electronegativity between carbon and hydrogen. However, the effect of these polar bonds cancels out due to the symmetrical arrangement of the CH3 and CH2 groups.
Therefore, the dipole moment of CH3-CH2-Cl is primarily determined by the polarity of the C-Cl bond. The bond length of C-Cl is approximately 1.78 Å, and the dipole moment can be calculated using the equation:
μ = Q × d
where μ is the dipole moment, Q is the partial charge on the chlorine atom (δ-), and d is the bond length.
Using the values for Q and d, we get:
μ = 1.03 D
where D is the unit for dipole moment (1 Debye = 3.336 × 10^-30 C m).
Therefore, the dipole moment of CH3-CH2-Cl is approximately 1.03 D.
The molecule has a polar covalent bond between the carbon and chlorine atoms, with the chlorine atom being more electronegative than the carbon atom. This results in a partial negative charge on the chlorine atom and a partial positive charge on the carbon atom.
In addition, the C-C and C-H bonds are also polar due to the difference in electronegativity between carbon and hydrogen. However, the effect of these polar bonds cancels out due to the symmetrical arrangement of the CH3 and CH2 groups.
Therefore, the dipole moment of CH3-CH2-Cl is primarily determined by the polarity of the C-Cl bond. The bond length of C-Cl is approximately 1.78 Å, and the dipole moment can be calculated using the equation:
μ = Q × d
where μ is the dipole moment, Q is the partial charge on the chlorine atom (δ-), and d is the bond length.
Using the values for Q and d, we get:
μ = 1.03 D
where D is the unit for dipole moment (1 Debye = 3.336 × 10^-30 C m).
Therefore, the dipole moment of CH3-CH2-Cl is approximately 1.03 D.
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Dipole moment of CH3-CH2-Cl > CH2=CH-Cl.a)Trueb)FalseCorrect answer...
Dipole moment of CH3-CH2-Cl > CH2=CH-Cl. This is due to resonance in vinyl chloride.
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Dipole moment of CH3-CH2-Cl > CH2=CH-Cl.a)Trueb)FalseCorrect answer is option 'A'. Can you explain this answer?
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