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If 2logx log y = log(x y) then the correct relation between x & y is a. y = x/(x - 1) b. y = (x ^ 2)/(x ^ 2 - 1) c. y = x/(x ^ 2 - 1) d. y = (x ^ 2)/(x ^ 2 1)?
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If 2logx log y = log(x y) then the correct relation between x & y ...
And y is:

2logx + logy = log(xy)
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If 2logx log y = log(x y) then the correct relation between x & y is a. y = x/(x - 1) b. y = (x ^ 2)/(x ^ 2 - 1) c. y = x/(x ^ 2 - 1) d. y = (x ^ 2)/(x ^ 2 1)?
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If 2logx log y = log(x y) then the correct relation between x & y is a. y = x/(x - 1) b. y = (x ^ 2)/(x ^ 2 - 1) c. y = x/(x ^ 2 - 1) d. y = (x ^ 2)/(x ^ 2 1)? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If 2logx log y = log(x y) then the correct relation between x & y is a. y = x/(x - 1) b. y = (x ^ 2)/(x ^ 2 - 1) c. y = x/(x ^ 2 - 1) d. y = (x ^ 2)/(x ^ 2 1)? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 2logx log y = log(x y) then the correct relation between x & y is a. y = x/(x - 1) b. y = (x ^ 2)/(x ^ 2 - 1) c. y = x/(x ^ 2 - 1) d. y = (x ^ 2)/(x ^ 2 1)?.
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