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How many geometrical isomers are possible in [Al(C2o4)3]3-?
  • a)
    0
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
How many geometrical isomers are possible in [Al(C2o4)3]3-?a)0b)2c)3d)...
Geometrical isomerism is a type of stereoisomerism that arises when a molecule has restricted rotation due to a double bond or a ring structure. In order for geometrical isomers to exist, there must be different groups attached to each atom of the double bond or each carbon of the ring structure.

[Al(C2O4)3]3- is a coordination complex in which the central metal ion, aluminum, is surrounded by six oxalate ligands. Each oxalate ligand has two carboxylate groups (-COO-) which can act as bidentate ligands, forming chelate rings with the aluminum ion.

However, in this case, there are no geometrical isomers possible for [Al(C2O4)3]3-. This is because all the oxalate ligands are identical and have the same orientation around the aluminum ion, leading to a symmetric structure. Therefore, there is no possibility of different groups attached to each atom of a double bond or each carbon of a ring structure, making geometrical isomers impossible.

Hence, the correct answer is option 'A' - 0 geometrical isomers are possible in [Al(C2O4)3]3-.
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Community Answer
How many geometrical isomers are possible in [Al(C2o4)3]3-?a)0b)2c)3d)...
The entity shown has a CN=6 as oxalate is a bidentate ligand. The structure of the entity will be same no matter which positions in the geometry each of the oxalate ligands occupy because their relative positions will remain the same in each case.
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How many geometrical isomers are possible in [Al(C2o4)3]3-?a)0b)2c)3d)4Correct answer is option 'A'. Can you explain this answer?
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