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For a square planar complex [Mabcd] (where M = central metal and abcd are monodentate ligands), the number of possible geometrical isomers are:
- a)1
- b)2
- c)3
- d)4
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
For a square planar complex [Mabcd] (where M = central metal and abcd ...
As...it is sqaure planar complex and ligand are monodantate...then M is central atom and 4 ligand will surround it...so fix any one of them and rotate another three of them...only three new structure will form....and hence answer is C
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For a square planar complex [Mabcd] (where M = central metal and abcd ...
Possible geometrical isomers for a square planar complex [Mabcd] are:
1. Trans- isomer: The ligands are arranged in a trans configuration with respect to each other. This means that two ligands are opposite to each other and the other two are also opposite to each other, forming a square. There is only one trans isomer possible for a square planar complex.
2. Cis- isomer: The ligands are arranged in a cis configuration with respect to each other. This means that two ligands are adjacent to each other and the other two are also adjacent to each other, forming a rectangle. There are three possible cis isomers possible for a square planar complex:
- cis-trans-cis: Two adjacent ligands are the same and the other two adjacent ligands are also the same.
- cis-cis-trans: Two adjacent ligands are the same and the other two opposite ligands are also the same.
- cis-trans-trans: Two opposite ligands are the same and the other two adjacent ligands are also the same.
Therefore, the total number of possible geometrical isomers for a square planar complex is 1 + 3 = 4. However, one of the cis isomers is a meso compound, which means that it is achiral and therefore identical to its mirror image. Hence, the number of distinct geometrical isomers is reduced to 3.
1. Trans- isomer: The ligands are arranged in a trans configuration with respect to each other. This means that two ligands are opposite to each other and the other two are also opposite to each other, forming a square. There is only one trans isomer possible for a square planar complex.
2. Cis- isomer: The ligands are arranged in a cis configuration with respect to each other. This means that two ligands are adjacent to each other and the other two are also adjacent to each other, forming a rectangle. There are three possible cis isomers possible for a square planar complex:
- cis-trans-cis: Two adjacent ligands are the same and the other two adjacent ligands are also the same.
- cis-cis-trans: Two adjacent ligands are the same and the other two opposite ligands are also the same.
- cis-trans-trans: Two opposite ligands are the same and the other two adjacent ligands are also the same.
Therefore, the total number of possible geometrical isomers for a square planar complex is 1 + 3 = 4. However, one of the cis isomers is a meso compound, which means that it is achiral and therefore identical to its mirror image. Hence, the number of distinct geometrical isomers is reduced to 3.
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For a square planar complex [Mabcd] (where M = central metal and abcd are monodentate ligands), the number of possible geometrical isomers are:a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer?
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