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What is the oxidation state of platinum in [PtCl6]2-
  • a)
    + 2
  • b)
    + 4
  • c)
    + 6
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
What is the oxidation state of platinum in [PtCl6]2-a)+ 2b)+ 4c)+ 6d)N...
x + 6 X – 1 = – 2
x – 6 = – 2
x = 6 – 2
x = + 4
Hence, the oxidation state of platinum in [PtCl6]2- is + 4.
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Most Upvoted Answer
What is the oxidation state of platinum in [PtCl6]2-a)+ 2b)+ 4c)+ 6d)N...
Understanding the Oxidation State of Platinum in [PtCl6]2-
To determine the oxidation state of platinum in the complex ion [PtCl6]2-, we need to analyze the overall charge and the contributions from the chloride ions.
Step 1: Identifying the Overall Charge
- The complex ion [PtCl6]2- has an overall charge of -2.
Step 2: Charge Contribution from Chloride Ions
- Each chloride ion (Cl-) has an oxidation state of -1.
- Since there are 6 chloride ions in the complex, their total contribution to the charge is:
- 6 Cl- = 6 * (-1) = -6.
Step 3: Setting Up the Equation
- Let the oxidation state of platinum (Pt) be x.
- The total charge equation can be set up as follows:
- x + (6 * -1) = -2.
Step 4: Solving for x
- This simplifies to:
- x - 6 = -2.
- Adding 6 to both sides gives:
- x = 4.
Conclusion
- The oxidation state of platinum in [PtCl6]2- is +4.
- Therefore, the correct answer is option 'b' (+4).
This systematic approach confirms that the oxidation state of platinum in the given complex is +4, aligning with the charge contributions from the surrounding chloride ions.
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Community Answer
What is the oxidation state of platinum in [PtCl6]2-a)+ 2b)+ 4c)+ 6d)N...
x + 6 X – 1 = – 2
x – 6 = – 2
x = 6 – 2
x = + 4
Hence, the oxidation state of platinum in [PtCl6]2- is + 4.
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What is the oxidation state of platinum in [PtCl6]2-a)+ 2b)+ 4c)+ 6d)None of the aboveCorrect answer is option 'B'. Can you explain this answer?
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