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There is an Ethernet port on a router were assigned an IP address of 172.16.112.1/25. Which of the following would be the valid subnet address of this host?
- a)172.16.112.0
- b)172.16.0.0
- c)172.16.96.0
- d)72.16.255.0
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
There is an Ethernet port on a router were assigned an IP address of 1...
Explanation:
To determine the valid subnet address of the given IP address, we need to determine the network portion of the IP address. The subnet mask for the given IP address is /25, which means the first 25 bits of the IP address are used for the network portion, and the remaining 7 bits are used for the host portion.
The valid subnet address is obtained by setting all the host bits to zero. Therefore, we need to determine the network address that corresponds to the given IP address.
The given IP address is 172.16.112.1/25. To determine the network address, we need to perform a logical AND operation between the IP address and the subnet mask:
IP address: 172.16.112.1
Subnet mask: 255.255.255.128 (/25)
Performing a logical AND operation between the IP address and the subnet mask gives us:
Network address: 172.16.112.0
Therefore, the valid subnet address for the given IP address is 172.16.112.0.
HTML-formatted answer:
To determine the valid subnet address of the given IP address, we need to determine the network portion of the IP address. The subnet mask for the given IP address is /25, which means the first 25 bits of the IP address are used for the network portion, and the remaining 7 bits are used for the host portion.
The valid subnet address is obtained by setting all the host bits to zero. Therefore, we need to determine the network address that corresponds to the given IP address.
The given IP address is 172.16.112.1/25. To determine the network address, we need to perform a logical AND operation between the IP address and the subnet mask:
IP address: 172.16.112.1
Subnet mask: 255.255.255.128 (/25)
Performing a logical AND operation between the IP address and the subnet mask gives us:
Network address: 172.16.112.0
Therefore, the valid subnet address for the given IP address is 172.16.112.0.
HTML-formatted answer:
Explanation:
To determine the valid subnet address of the given IP address, we need to determine the network portion of the IP address. The subnet mask for the given IP address is /25, which means the first 25 bits of the IP address are used for the network portion, and the remaining 7 bits are used for the host portion.
The valid subnet address is obtained by setting all the host bits to zero. Therefore, we need to determine the network address that corresponds to the given IP address.
The given IP address is 172.16.112.1/25. To determine the network address, we need to perform a logical AND operation between the IP address and the subnet mask:
- IP address: 172.16.112.1
- Subnet mask: 255.255.255.128 (/25)
Performing a logical AND operation between the IP address and the subnet mask gives us:
- Network address: 172.16.112.0
Therefore, the valid subnet address for the given IP address is 172.16.112.0.
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Community Answer
There is an Ethernet port on a router were assigned an IP address of 1...
The correct option is (a)
172.16.112.0
Concept:
Subnetting is the process of creating smaller networks called subnets by taking bits from the HOST portion of an IP address.
Explanation:
Given IP IS 172.16.112.1/25 ⇒ NID (Network ID) is 25 bits.
We know that a subnet mask is obtained by replacing all NID(Net ID) bits with 1 and HID(Host ID) bits with 0.
So SM is 255.255.255.10000000 (the First 25 bits are NID and the last 7 bits are HID).
i.e, SM is 255.255.255.128.
Now perform Bitwise AND operation between subnet address and given IP address.
⇒ (255.255.255.128) and (172.16.112.1) = 172.16.112.0
172.16.112.0
Concept:
Subnetting is the process of creating smaller networks called subnets by taking bits from the HOST portion of an IP address.
Explanation:
Given IP IS 172.16.112.1/25 ⇒ NID (Network ID) is 25 bits.
We know that a subnet mask is obtained by replacing all NID(Net ID) bits with 1 and HID(Host ID) bits with 0.
So SM is 255.255.255.10000000 (the First 25 bits are NID and the last 7 bits are HID).
i.e, SM is 255.255.255.128.
Now perform Bitwise AND operation between subnet address and given IP address.
⇒ (255.255.255.128) and (172.16.112.1) = 172.16.112.0
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There is an Ethernet port on a router were assigned an IP address of 172.16.112.1/25. Which of the following would be the valid subnet address of this host?a)172.16.112.0b)172.16.0.0c)172.16.96.0d)72.16.255.0Correct answer is option 'A'. Can you explain this answer?
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There is an Ethernet port on a router were assigned an IP address of 172.16.112.1/25. Which of the following would be the valid subnet address of this host?a)172.16.112.0b)172.16.0.0c)172.16.96.0d)72.16.255.0Correct answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about There is an Ethernet port on a router were assigned an IP address of 172.16.112.1/25. Which of the following would be the valid subnet address of this host?a)172.16.112.0b)172.16.0.0c)172.16.96.0d)72.16.255.0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There is an Ethernet port on a router were assigned an IP address of 172.16.112.1/25. Which of the following would be the valid subnet address of this host?a)172.16.112.0b)172.16.0.0c)172.16.96.0d)72.16.255.0Correct answer is option 'A'. Can you explain this answer?.
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