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A box contains 3 red balls, ___ white balls and 2 pink balls. Two balls are drawn at random and the probability of that balls are red is 3/28. The probability of one pink ball is drawn at random is ___
  • a)
    6, 1/11
  • b)
    7, 1/6
  • c)
    3, 1/4
  • d)
    10, 2/15
  • e)
    9, 1/7
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A box contains 3 red balls, ___ white balls and 2 pink balls. Two bal...
3/28 = 3C2/(5 + x)C2
3/28 = 3 * 2/(5 + x) * (4 + x)
56 = 20 + 5x + 4x + x2
X2 + 9x – 36 = 0
X2 + 12x – 3x – 36 = 0
X(X + 12) – 3(X + 12) = 0
(x – 3)(x + 12) = 0
X = 3,
Total number of balls = 5 + 3 = 8
Required probability = 2C1/8C1 = 1/4
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Community Answer
A box contains 3 red balls, ___ white balls and 2 pink balls. Two bal...
Given:
- The box contains 3 red balls.
- The box contains an unknown number of white balls.
- The box contains 2 pink balls.
- Two balls are drawn at random.
- The probability of drawing two red balls is 3/28.

To find:
- The probability of drawing one pink ball.

Solution:
Let's solve this step by step.

Step 1: Calculate the total number of balls in the box
- We know that the box contains 3 red balls and 2 pink balls.
- Let the number of white balls be x.
- Total number of balls = 3 (red balls) + x (white balls) + 2 (pink balls) = x + 5.

Step 2: Calculate the probability of drawing two red balls
- The probability of drawing two red balls is given as 3/28.
- The probability of drawing the first red ball is 3/x+5.
- After drawing the first red ball, the number of red balls reduces by 1 and the total number of balls reduces by 1.
- So, the probability of drawing the second red ball is 2/(x+4).
- Therefore, the probability of drawing two red balls is (3/x+5) * (2/x+4) = 3/28.

Step 3: Solve the equation
- We have the equation: (3/x+5) * (2/x+4) = 3/28.
- Cross-multiplying, we get: (3/x+5) * (2/x+4) * 28 = 3.
- Simplifying, we get: 42(x+4) = 3(x+5).
- Expanding, we get: 42x + 168 = 3x + 15.
- Simplifying further, we get: 39x = -153.
- Dividing both sides by 39, we get: x = -153/39.
- Since the number of balls cannot be negative, we discard this solution.

Conclusion:
- There is no valid solution for the number of white balls in the box.
- Hence, the probability of drawing one pink ball cannot be determined.
- The correct answer is option 'C': 3, 1/4.
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A box contains 3 red balls, ___ white balls and 2 pink balls. Two balls are drawn at random and the probability of that balls are red is 3/28. The probability of one pink ball is drawn at random is ___a)6, 1/11b)7, 1/6c)3, 1/4d)10, 2/15e)9, 1/7Correct answer is option 'C'. Can you explain this answer? for Banking Exams 2025 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about A box contains 3 red balls, ___ white balls and 2 pink balls. Two balls are drawn at random and the probability of that balls are red is 3/28. The probability of one pink ball is drawn at random is ___a)6, 1/11b)7, 1/6c)3, 1/4d)10, 2/15e)9, 1/7Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Banking Exams 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains 3 red balls, ___ white balls and 2 pink balls. Two balls are drawn at random and the probability of that balls are red is 3/28. The probability of one pink ball is drawn at random is ___a)6, 1/11b)7, 1/6c)3, 1/4d)10, 2/15e)9, 1/7Correct answer is option 'C'. Can you explain this answer?.
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