Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Consider the array L = [1, 2, 3, 4, 5, 6, 7, ...
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Consider the array L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]. Suppose you’re searching for the value 3 using binary search method. What is the value of the variable last after two iterations?
- a)14
- b)2
- c)6
- d)3
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Consider the array L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14,...
The starting values of first and last are 0 and 14 respectively.
The iterations are shown below:
Therefore, the value of the variable last is 2 after the first two iterations.
Important points:
The iterations are shown below:
Therefore, the value of the variable last is 2 after the first two iterations.
Important points:
- The binary search method works on sorted arrays only.
- It checks the middle element with the search element. If it matches, the index is returned.
- Otherwise, if the search element is lesser than the middle element then the algorithm repeats the process in the left half of the array. Else, it searches in the right half of the array.
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Community Answer
Consider the array L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14,...
Want to find the sum of all the even numbers in the array L.
To do this, you can iterate through each element in the array and check if it is even. If it is even, add it to a running total. Here is the code to achieve this:
```python
L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
sum_even = 0
for num in L:
if num % 2 == 0:
sum_even += num
print(sum_even)
```
Output:
```
56
```
In this code, we initialize a variable `sum_even` to 0 to keep track of the sum of even numbers. Then, we iterate through each element `num` in the array `L`. Inside the loop, we use the modulo operator `%` to check if `num` is divisible by 2 (i.e., even). If it is, we add it to `sum_even`. Finally, we print `sum_even`, which gives us the sum of all even numbers in the array.
To do this, you can iterate through each element in the array and check if it is even. If it is even, add it to a running total. Here is the code to achieve this:
```python
L = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
sum_even = 0
for num in L:
if num % 2 == 0:
sum_even += num
print(sum_even)
```
Output:
```
56
```
In this code, we initialize a variable `sum_even` to 0 to keep track of the sum of even numbers. Then, we iterate through each element `num` in the array `L`. Inside the loop, we use the modulo operator `%` to check if `num` is divisible by 2 (i.e., even). If it is, we add it to `sum_even`. Finally, we print `sum_even`, which gives us the sum of all even numbers in the array.
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Question Description
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