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Find the value of a4 for the recurrence relation an = 2an-1 + 3, with a0 = 6.
- a)320
- b)221
- c)141
- d)65
Correct answer is option 'C'. Can you explain this answer?
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Find the value of a4for the recurrence relation an= 2an-1+ 3, with a0=...
When n = 1, a1 = 2a0 + 3, Now a2 = 2a1 + 3. By substitution, we get a2 = 2(2a0 + 3) + 3.
Regrouping the terms, we get a4 = 141, where a0 = 6.
Regrouping the terms, we get a4 = 141, where a0 = 6.
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Find the value of a4for the recurrence relation an= 2an-1+ 3, with a0=...
To find the value of a4 for the given recurrence relation, we need to understand the pattern and calculate each term step by step.
Given recurrence relation: an = 2an-1 + 3
Let's calculate each term one by one:
a0 = 6 (given)
a1 = 2a0 + 3 = 2(6) + 3 = 12 + 3 = 15
a2 = 2a1 + 3 = 2(15) + 3 = 30 + 3 = 33
a3 = 2a2 + 3 = 2(33) + 3 = 66 + 3 = 69
a4 = 2a3 + 3 = 2(69) + 3 = 138 + 3 = 141
Therefore, the value of a4 for the given recurrence relation is 141.
Thus, the correct answer is option 'C'.
Given recurrence relation: an = 2an-1 + 3
Let's calculate each term one by one:
a0 = 6 (given)
a1 = 2a0 + 3 = 2(6) + 3 = 12 + 3 = 15
a2 = 2a1 + 3 = 2(15) + 3 = 30 + 3 = 33
a3 = 2a2 + 3 = 2(33) + 3 = 66 + 3 = 69
a4 = 2a3 + 3 = 2(69) + 3 = 138 + 3 = 141
Therefore, the value of a4 for the given recurrence relation is 141.
Thus, the correct answer is option 'C'.
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Find the value of a4for the recurrence relation an= 2an-1+ 3, with a0= 6.a)320b)221c)141d)65Correct answer is option 'C'. Can you explain this answer?
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