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What is the recurrence relation for the sequence 1, 3, 7, 15, 31, 63,…?
  • a)
    an = 3an-1−2an+2
  • b)
    an = 3an-1−2an-2
  • c)
    an = 3an-1−2an-1
  • d)
    an = 3an-1−2an-3
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
What is the recurrence relation for the sequence 1, 3, 7, 15, 31, 63,&...
To find the recurrence relation for the sequence 1, 3, 7, 15, 31, 63, we can observe that each term is obtained by doubling the previous term and then subtracting 1.

Let's denote the nth term of the sequence as aₙ.

From the given sequence, we have:
a₁ = 1
a₂ = 3
a₃ = 7
a₄ = 15
a₅ = 31
a₆ = 63

We can see that aₙ = 2aₙ₋₁ - 1 for n ≥ 2.

Therefore, the recurrence relation for the sequence 1, 3, 7, 15, 31, 63 is:
aₙ = 2aₙ₋₁ - 1, for n ≥ 2.
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Community Answer
What is the recurrence relation for the sequence 1, 3, 7, 15, 31, 63,&...
The recurrence relation for the sequence 1, 3, 7, 15, 31, 63,… should be an = 3an-1−2an-2. The solution for A: A=1/1 − 3x + 2x2.
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What is the recurrence relation for the sequence 1, 3, 7, 15, 31, 63,…?a)an= 3an-1−2an+2b)an= 3an-1−2an-2c)an= 3an-1−2an-1d)an= 3an-1−2an-3Correct answer is option 'B'. Can you explain this answer?
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