Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > A 4 × 1 Multiplexer is shown in the Fig...
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A 4 × 1 Multiplexer is shown in the Figure below. The output Z is
- a)A NOR C
- b)B NOR C
- c)B XOR C
- d)A XOR C
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A 4 × 1 Multiplexer is shown in the Figure below. The output Z i...
Concept:
In a 4 × 1 MUX
Truth-Table is given as:
Truth-Table is given as:
Y = Output = S̅1 S̅0 I0 + S̅1 S0 I1 + S1 S̅0 I2 + S1 S0 I3
MUX contains AND gate followed by OR gate
Calculation:
Given:
Z = Output = A̅B̅C + A̅BC + AB̅C̅ + ABC̅
Z = A̅C(B̅ + B) + AC̅(B̅ + B)
Z = A̅C + AC̅
Z = A XOR C
Hence, option 4 is correct.
MUX contains AND gate followed by OR gate
Calculation:
Given:
Z = Output = A̅B̅C + A̅BC + AB̅C̅ + ABC̅
Z = A̅C(B̅ + B) + AC̅(B̅ + B)
Z = A̅C + AC̅
Z = A XOR C
Hence, option 4 is correct.
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Community Answer
A 4 × 1 Multiplexer is shown in the Figure below. The output Z i...
Concept:
In a 4 × 1 MUX
Truth-Table is given as:
Truth-Table is given as:
Y = Output = S̅1 S̅0 I0 + S̅1 S0 I1 + S1 S̅0 I2 + S1 S0 I3
MUX contains AND gate followed by OR gate
Calculation:
Given:
Z = Output = A̅B̅C + A̅BC + AB̅C̅ + ABC̅
Z = A̅C(B̅ + B) + AC̅(B̅ + B)
Z = A̅C + AC̅
Z = A XOR C
Hence, option 4 is correct.
MUX contains AND gate followed by OR gate
Calculation:
Given:
Z = Output = A̅B̅C + A̅BC + AB̅C̅ + ABC̅
Z = A̅C(B̅ + B) + AC̅(B̅ + B)
Z = A̅C + AC̅
Z = A XOR C
Hence, option 4 is correct.
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A 4 × 1 Multiplexer is shown in the Figure below. The output Z isa)A NOR Cb)B NOR Cc)B XOR Cd)A XOR CCorrect answer is option 'D'. Can you explain this answer?
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