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Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,
I) x2+ 18x + 72 = 0
II) y2 + 32y + 247 = 0
- a)x < />
- b)x > y
- c)x ≤ y
- d)x ≥ y
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Following question contains two equations as I and II. You have to so...
To solve the given equations, we need to find the values of x and y that satisfy both equations. Let's solve them one by one:
I) x^2 - 18x + 72 = 0
This is a quadratic equation. To solve it, we can factorize it or use the quadratic formula.
Factorizing the equation:
(x - 6)(x - 12) = 0
Setting each factor equal to zero:
x - 6 = 0 or x - 12 = 0
Solving for x:
x = 6 or x = 12
II) y^2 - 32y + 247 = 0
Again, this is a quadratic equation. To solve it, we can factorize it or use the quadratic formula.
Factorizing the equation:
(y - 13)(y - 19) = 0
Setting each factor equal to zero:
y - 13 = 0 or y - 19 = 0
Solving for y:
y = 13 or y = 19
Relationship between the equations:
Now, let's analyze the relationship between x and y based on the solutions we obtained.
x = 6 or x = 12
y = 13 or y = 19
From the solutions, we can see that both x and y have multiple values. There is no specific relationship between the two equations in terms of the values of x and y.
However, we can compare the values of x and y to determine if one is greater than the other or if they are equal.
Comparing the values:
x = 6, y = 13 or x = 6, y = 19
x = 12, y = 13 or x = 12, y = 19
From the comparisons, we can see that in all cases, x is less than y. Therefore, the correct relationship between the equations is:
x < />
Hence, the correct answer is option B) x < y.="" />
I) x^2 - 18x + 72 = 0
This is a quadratic equation. To solve it, we can factorize it or use the quadratic formula.
Factorizing the equation:
(x - 6)(x - 12) = 0
Setting each factor equal to zero:
x - 6 = 0 or x - 12 = 0
Solving for x:
x = 6 or x = 12
II) y^2 - 32y + 247 = 0
Again, this is a quadratic equation. To solve it, we can factorize it or use the quadratic formula.
Factorizing the equation:
(y - 13)(y - 19) = 0
Setting each factor equal to zero:
y - 13 = 0 or y - 19 = 0
Solving for y:
y = 13 or y = 19
Relationship between the equations:
Now, let's analyze the relationship between x and y based on the solutions we obtained.
x = 6 or x = 12
y = 13 or y = 19
From the solutions, we can see that both x and y have multiple values. There is no specific relationship between the two equations in terms of the values of x and y.
However, we can compare the values of x and y to determine if one is greater than the other or if they are equal.
Comparing the values:
x = 6, y = 13 or x = 6, y = 19
x = 12, y = 13 or x = 12, y = 19
From the comparisons, we can see that in all cases, x is less than y. Therefore, the correct relationship between the equations is:
x < />
Hence, the correct answer is option B) x < y.="" />
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Community Answer
Following question contains two equations as I and II. You have to so...
From I => x2 + 18x + 72 = 0
=> x2 + 6x + 12x + 72 = 0
=> x(x + 6) +12(x + 6) = 0
=> (x + 6) (x + 12) = 0
=> x = -6, -12
From II => y2 + 32y + 247 = 0
=> y2 + 13y + 19y + 247 = 0
=> y(y + 13) +19(y + 13) = 0
=> (y + 13) (y + 19) = 0
=> y = -13, -19
Hence, x > y
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Solutions for Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,I) x2+ 18x + 72 = 0II) y2 + 32y + 247 = 0a)x b)x > yc)x ≤ yd)x ≥ ye)None of theseCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Banking Exams.
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