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A galvanometer with a full scale current of 10 mA has a resistance of 1000Ω. The multiplying power (the ratio of measured current to galvanometer current) of 100Ω shunt with the galvanometer is (Answer up to the nearest integer)
Correct answer is '11'. Can you explain this answer?
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A galvanometer with a full scale current of 10 mA has a resistance of...
Galvanometer and Shunt

A galvanometer is an instrument used to measure small electrical currents. It consists of a coil suspended between the poles of a permanent magnet. When a current passes through the coil, it experiences a torque that deflects the coil. The deflection is proportional to the current passing through the coil.

In order to measure larger currents, a shunt resistor is connected in parallel with the galvanometer. The shunt resistor diverts a portion of the current away from the galvanometer, allowing it to measure only a fraction of the total current.

Given Data

- Full scale current of the galvanometer (Ig) = 10 mA
- Resistance of the galvanometer (Rg) = 1000 Ω
- Resistance of the shunt (Rs) = 100 Ω

Calculating the Multiplying Power

The multiplying power is the ratio of the measured current (Im) to the galvanometer current (Ig).

Using Ohm's Law, we can calculate the galvanometer current as:

Ig = V/Rg

where V is the voltage across the galvanometer. Since the galvanometer is connected in parallel with the shunt, the voltage across both of them is the same.

Similarly, we can calculate the current passing through the shunt resistor as:

Is = V/Rs

The total current passing through the galvanometer and the shunt is the sum of Ig and Is:

Itotal = Ig + Is

The measured current is the current passing through the shunt resistor:

Im = Is

The multiplying power is then given by:

Multiplying Power = Im/Ig = Is/(Ig + Is)

Plugging in the values:

Multiplying Power = Is/(Ig + Is) = (V/Rs)/[(V/Rg) + (V/Rs)]

Simplifying the expression:

Multiplying Power = Rs/(Rg + Rs)

Substituting the given values:

Multiplying Power = 100/(1000 + 100) = 100/1100

Rounding the answer to the nearest integer:

Multiplying Power = 0.0909 ≈ 11

Therefore, the multiplying power of the shunt with the galvanometer is approximately 11.
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Community Answer
A galvanometer with a full scale current of 10 mA has a resistance of...
We have to obtain n = I/I1
I1 + I2 = I
I1 + 10I1 = I
11I1 = I
N = I/I1 = 11
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A galvanometer with a full scale current of 10 mA has a resistance of 1000Ω. The multiplying power (the ratio of measured current to galvanometer current) of 100Ω shunt with the galvanometer is (Answer up to the nearest integer)Correct answer is '11'. Can you explain this answer?
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