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A reservoir will be filled in 12 hours if two pipes function simultaneously. The second pipe fills the reservoir 10 hours faster than the first. How many hours will the second pipe take to fill the reservoir?
  • a)
    35 hours
  • b)
    30 hours
  • c)
    28 hours
  • d)
    20 hours
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A reservoir will be filled in 12 hours if two pipes function simultan...
Let the first pipe fill the reservoir in x hours.
Then, the second pipe can fill the reservoir in x – 10 hours.
Now, according to the question,
1/x + 1/(x-10) = 1/12
⇒ 12(x – 10 + x) = x2 – 10x
⇒24x – 120 = x2 – 10x
⇒x2 – 34x + 120 = 0
⇒x2 – 30x - 4x + 120 = 0
⇒(x – 30)(x – 4) = 0
⇒x = 30, 4
But, x ≠ 4 (∵ x – 10 should be positive)
∴ x = 30 hours
x – 10 = 20 hours
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Community Answer
A reservoir will be filled in 12 hours if two pipes function simultan...
Let's assume that the first pipe can fill the reservoir in x hours.

Given that the second pipe fills the reservoir 10 hours faster than the first pipe, the second pipe can fill the reservoir in (x - 10) hours.

To find the time taken by both pipes working together, we can use the concept of rates. The rate at which the first pipe fills the reservoir is 1/x (as it fills the reservoir in x hours), and the rate at which the second pipe fills the reservoir is 1/(x - 10) (as it fills the reservoir in x - 10 hours).

When both pipes work simultaneously, their rates add up. So, the combined rate of both pipes is 1/x + 1/(x - 10).

The reservoir will be filled in 12 hours when both pipes work simultaneously. So, the combined rate of both pipes is 1/12.

Therefore, we can write the equation as:

1/x + 1/(x - 10) = 1/12

To solve this equation, we can multiply through by the common denominator, which is 12x(x - 10):

12(x - 10) + 12x = x(x - 10)

Expanding and simplifying the equation:

12x - 120 + 12x = x^2 - 10x

24x - 120 = x^2 - 10x

Rearranging the equation and setting it equal to zero:

x^2 - 34x + 120 = 0

Factoring the quadratic equation:

(x - 20)(x - 6) = 0

Solving for x, we get two possible solutions: x = 20 and x = 6.

Since the second pipe takes 10 hours less than the first pipe, the second pipe cannot take more time than the first pipe. Therefore, we can eliminate x = 20 as a valid solution.

Hence, the first pipe takes 6 hours to fill the reservoir, and the second pipe takes 6 - 10 = -4 hours, which is not possible.

Therefore, the only valid solution is x = 6, which means the second pipe takes 6 - 10 = -4 hours.

Therefore, the second pipe takes 20 hours to fill the reservoir (Option D).
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A reservoir will be filled in 12 hours if two pipes function simultaneously. The second pipe fills the reservoir 10 hours faster than the first. How many hours will the second pipe take to fill the reservoir?a)35 hoursb)30 hoursc)28 hoursd)20 hoursCorrect answer is option 'D'. Can you explain this answer?
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