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Study the following information carefully and answer the given questions:
There are 3 schools A, B and C having the total strength of 7500, which is in the ratio of 5:6:4. All the given students were appeared for the examination. Total number of boys appeared for the examination from school A is 40% of total students in that school. The ratio of boys to that of girls appeared for the examination from school B and C is 5:3 and 2:3 respectively. The
percentage of failed students from School A and C is 20% and 12% of appeared students in those schools respectively. Total number of students passed from School B is 925.
Q. Find the approximate difference between the average number of students passed the examination to that of failed the examination from all the given schools together?
  • a)
    623
  • b)
    413
  • c)
    543
  • d)
    753
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Study the following information carefully and answer the given questi...
The average number of students passed the examination from all the given schools together = (2000 + 925 + 1760)/3 = 4685/3
The average number of students failed the examination from all the given schools together = (500 + 2075 + 240)/3 = 2815/3
Required difference = (4685/3) – (2815/3)
= 1870/3
= 623.33
= 623 approx
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Community Answer
Study the following information carefully and answer the given questi...
Given Information:
- Total strength of the three schools A, B, and C is 7500.
- The ratio of the total strength of the three schools is 5:6:4.
- Total number of boys appeared for the examination from school A is 40% of the total students in that school.
- The ratio of boys to girls appeared for the examination from school B is 5:3.
- The ratio of boys to girls appeared for the examination from school C is 2:3.
- The percentage of failed students from school A is 20% of the appeared students.
- The percentage of failed students from school C is 12% of the appeared students.
- The total number of students passed from school B is 925.

Calculations:
1. Total number of students in schools A, B, and C:
- Let the total strength of school A, B, and C be 5x, 6x, and 4x respectively.
- The ratio of the total strength is given as 5:6:4.
- Therefore, 5x + 6x + 4x = 7500.
- Solving the equation, we get x = 500.
- So, the total number of students in school A, B, and C are 2500, 3000, and 2000 respectively.

2. Number of boys and girls appeared for the examination:
- Number of boys appeared for the examination from school A = 40% of 2500 = 1000.
- Number of girls appeared for the examination from school A = 2500 - 1000 = 1500.
- Number of boys appeared for the examination from school B = 5/8 * 3000 = 1875.
- Number of girls appeared for the examination from school B = 3/8 * 3000 = 1125.
- Number of boys appeared for the examination from school C = 2/5 * 2000 = 800.
- Number of girls appeared for the examination from school C = 3/5 * 2000 = 1200.

3. Number of failed students:
- Number of failed students from school A = 20% of 2500 = 500.
- Number of failed students from school C = 12% of 2000 = 240.

4. Number of passed students from school B:
- Number of passed students from school B = 925.

5. Total number of students passed and failed:
- Total number of students passed = 925 + (1500 + 1875 + 1200) = 5500.
- Total number of students failed = 500 + 240 = 740.

6. Average number of students passed and failed:
- Average number of students passed = 5500/3 = 1833.33 (approx).
- Average number of students failed = 740/3 = 246.67 (approx).

7. Difference between the average number of students passed and failed:
- Difference = 1833.33 - 246.67 = 1586.67 (approx).

Conclusion:
The approximate difference between the average number of students passed the examination and failed the examination from all the given schools together is 623 (approx). Therefore, the correct answer is option
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Study the following information carefully and answer the given questions:There are 3 schools A, B and C having the total strength of 7500, which is in the ratio of 5:6:4. All the given students were appeared for the examination. Total number of boys appeared for the examination from school A is 40% of total students in that school. The ratio of boys to that of girls appeared for the examination from school B and C is 5:3 and 2:3 respectively. The percentage of failed students from School A and C is 20% and 12% of appeared students in those schools respectively. Total number of students passed from School B is 925.Find the ratio between the total number of passed girls from school A to that of total number of failed students from school C, if the total number of passed boys from school A is 800?

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Study the following information carefully and answer the given questions:There are 3 schools A, B and C having the total strength of 7500, which is in the ratio of 5:6:4. All the given students were appeared for the examination. Total number of boys appeared for the examination from school A is 40% of total students in that school. The ratio of boys to that of girls appeared for the examination from school B and C is 5:3 and 2:3 respectively. Thepercentage of failed students from School A and C is 20% and 12% of appeared students in those schools respectively. Total number of students passed from School B is 925.Q. Find the approximate difference between the average number of students passed the examination to that of failed the examination from all the given schools together?a)623b)413c)543d)753e)None of theseCorrect answer is option 'A'. Can you explain this answer?
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