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For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, are
- a)3.50 m and 53°7'48'' NW
- b)0.35 m and 53.13°SE
- c)2.45 m and 53°7'48'' NW
- d)3.50 m and 53.13°SE
Correct answer is option 'A'. Can you explain this answer?
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For a given traverse, latitudes and departures are calculated and it ...
Sum of latitudes (ΣL) = +2.1 m
Sum of departures (ΣD) = -2.8 m
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For a given traverse, latitudes and departures are calculated and it ...
Given information:
- Sum of latitudes = 2.1 m
- Sum of departures = -2.8 m
To find:
- Length and bearing of the closing error
Explanation:
1. Introduction:
- In surveying, traverse is a series of connected lines that represent a closed polygon or any other closed figure.
- The latitudes and departures are the measured distances in the north-south and east-west directions, respectively.
2. Calculation of closing error:
- The closing error is the discrepancy between the calculated and measured values of the traverse.
- The closing error can be calculated by summing up the latitudes and departures.
- In this case, the sum of latitudes is 2.1 m and the sum of departures is -2.8 m.
- Therefore, the closing error is the vector sum of these two values, which is equal to (2.1 m, -2.8 m).
3. Calculation of length and bearing:
- The length of the closing error can be found using the Pythagorean theorem.
- The length of the closing error is given by the formula: L = sqrt(latitude^2 + departure^2)
- Substituting the given values, we have L = sqrt((2.1)^2 + (-2.8)^2) = sqrt(4.41 + 7.84) = sqrt(12.25) = 3.50 m.
- The bearing of the closing error can be calculated using the formula: B = atan(latitude / departure)
- Substituting the given values, we have B = atan(2.1 / -2.8) = atan(-0.75) = -38.66°.
- Since the bearing is negative, we need to convert it to the northwest quadrant.
- The bearing in the northwest quadrant is given by B = 180° + B = 180° - 38.66° = 141.34°.
- Converting 141.34° to degrees, minutes, and seconds, we get 141°7'48'' NW.
4. Final answer:
- The length of the closing error is 3.50 m.
- The bearing of the closing error is 141°7'48'' NW.
Therefore, the correct answer is option A) 3.50 m and 141°7'48'' NW.
- Sum of latitudes = 2.1 m
- Sum of departures = -2.8 m
To find:
- Length and bearing of the closing error
Explanation:
1. Introduction:
- In surveying, traverse is a series of connected lines that represent a closed polygon or any other closed figure.
- The latitudes and departures are the measured distances in the north-south and east-west directions, respectively.
2. Calculation of closing error:
- The closing error is the discrepancy between the calculated and measured values of the traverse.
- The closing error can be calculated by summing up the latitudes and departures.
- In this case, the sum of latitudes is 2.1 m and the sum of departures is -2.8 m.
- Therefore, the closing error is the vector sum of these two values, which is equal to (2.1 m, -2.8 m).
3. Calculation of length and bearing:
- The length of the closing error can be found using the Pythagorean theorem.
- The length of the closing error is given by the formula: L = sqrt(latitude^2 + departure^2)
- Substituting the given values, we have L = sqrt((2.1)^2 + (-2.8)^2) = sqrt(4.41 + 7.84) = sqrt(12.25) = 3.50 m.
- The bearing of the closing error can be calculated using the formula: B = atan(latitude / departure)
- Substituting the given values, we have B = atan(2.1 / -2.8) = atan(-0.75) = -38.66°.
- Since the bearing is negative, we need to convert it to the northwest quadrant.
- The bearing in the northwest quadrant is given by B = 180° + B = 180° - 38.66° = 141.34°.
- Converting 141.34° to degrees, minutes, and seconds, we get 141°7'48'' NW.
4. Final answer:
- The length of the closing error is 3.50 m.
- The bearing of the closing error is 141°7'48'' NW.
Therefore, the correct answer is option A) 3.50 m and 141°7'48'' NW.
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For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, area)3.50 m and 53°7'48'' NWb)0.35 m and 53.13°SEc)2.45 m and 53°7'48'' NWd)3.50 m and 53.13°SECorrect answer is option 'A'. Can you explain this answer?
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For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, area)3.50 m and 53°7'48'' NWb)0.35 m and 53.13°SEc)2.45 m and 53°7'48'' NWd)3.50 m and 53.13°SECorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, area)3.50 m and 53°7'48'' NWb)0.35 m and 53.13°SEc)2.45 m and 53°7'48'' NWd)3.50 m and 53.13°SECorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, area)3.50 m and 53°7'48'' NWb)0.35 m and 53.13°SEc)2.45 m and 53°7'48'' NWd)3.50 m and 53.13°SECorrect answer is option 'A'. Can you explain this answer?.
For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, area)3.50 m and 53°7'48'' NWb)0.35 m and 53.13°SEc)2.45 m and 53°7'48'' NWd)3.50 m and 53.13°SECorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, area)3.50 m and 53°7'48'' NWb)0.35 m and 53.13°SEc)2.45 m and 53°7'48'' NWd)3.50 m and 53.13°SECorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, area)3.50 m and 53°7'48'' NWb)0.35 m and 53.13°SEc)2.45 m and 53°7'48'' NWd)3.50 m and 53.13°SECorrect answer is option 'A'. Can you explain this answer?.
Solutions for For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, area)3.50 m and 53°7'48'' NWb)0.35 m and 53.13°SEc)2.45 m and 53°7'48'' NWd)3.50 m and 53.13°SECorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
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ample number of questions to practice For a given traverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 m and the sum of departures is equal to -2.8 m. The length and bearing of the losing error, respectively, area)3.50 m and 53°7'48'' NWb)0.35 m and 53.13°SEc)2.45 m and 53°7'48'' NWd)3.50 m and 53.13°SECorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
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