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For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :
- a)2.45 m and 53° 7'48'' NW
- b)3.50 m and 53° 7'48'' NW
- c)0.35 m and 53.13° SE
- d)3.50 and 53.13° SE
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
For a given transverse, latitudes and departures are calculated and it...
Sum of latitude, ΣL= +2.1 m
Sum of departure, ΣD= −2.8 m
Bearing,
θ = 5307 ' 48.37 "
Hence, the correct option is (B).
Sum of departure, ΣD= −2.8 m
Bearing,
θ = 5307 ' 48.37 "
Hence, the correct option is (B).
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For a given transverse, latitudes and departures are calculated and it...
Calculation of Closing Error Length and Bearing
Given Data:
- Sum of latitudes = +2.1
- Sum of departures = -2.8
Calculations:
- Closing error = sqrt((sum of latitudes)^2 + (sum of departures)^2)
- Closing error = sqrt((2.1)^2 + (-2.8)^2)
- Closing error = sqrt(4.41 + 7.84)
- Closing error = sqrt(12.25)
- Closing error = 3.50 m
Angle Calculation:
- tan(bearing) = (sum of latitudes) / (sum of departures)
- tan(bearing) = 2.1 / -2.8
- bearing = atan(2.1 / -2.8)
- bearing = -37.38°
- Adjusted bearing = 360° - 37.38°
- Adjusted bearing = 322.62°
- Converted to the NW direction = 322.62° - 270° = 52.62°
- Converted to the NW direction = 52.62° + 360° = 412.62°
- Bearing = 412.62° - 360° = 52.62°
Therefore, the length of the closing error is 3.50 m and the bearing is 52.62° NW. So, option B is correct.
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For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer?
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For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer?.
For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer?.
Solutions for For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
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For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer?, a detailed solution for For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of For a given transverse, latitudes and departures are calculated and it is found that sum of latitudes is equal to +2.1 and the sum of departures is equal to – 2.8 m. The length and bearing of the closing error, respectively, are :a)2.45 m and 53° 748 NW b)3.50 m and 53° 748 NWc)0.35 m and 53.13° SE d)3.50 and 53.13° SECorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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