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A 420 V, 6 pole, 50 Hz star connected induction rotor has stator impedance of 0.07 + j 0.3 ohms and stand still impedance referred to stator is 0.08 + j 0.37 ohms. If the magnetizing current is neglected, the slip at maximum internal torque developed is
  • a)
    0.125
  • b)
    0.233
  • c)
    0.1187
  • d)
    0.286
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A 420 V, 6 pole, 50 Hz star connected induction rotor has stator impe...
Given data:
- Voltage (V) = 420 V
- Number of poles (p) = 6
- Frequency (f) = 50 Hz
- Stator impedance (Z₁) = 0.07 + j0.3 ohms
- Standstill impedance referred to stator (Z₂) = 0.08 + j0.37 ohms

To find: Slip at maximum internal torque developed

Formula:
Synchronous speed (Ns) = (120 * f) / p
Slip (S) = (Ns - N) / Ns
Where Ns is the synchronous speed, and N is the rotor speed.

Solution:
1. Calculate synchronous speed (Ns):
Ns = (120 * f) / p
= (120 * 50) / 6
= 1000 RPM

2. Calculate rotor speed (N):
The rotor speed is the speed at which the maximum internal torque is developed. At this speed, the slip is maximum. Therefore, the slip is zero.

3. Calculate standstill rotor impedance (Z₂):
Z₂ = Z₁ + (Z₁^2 / Zl)
Where Zl is the load impedance.

4. Let Zl = 0 (short-circuited rotor)
Z₂ = Z₁ + (Z₁^2 / Zl)
= Z₁ + (Z₁^2 / 0)
= Z₁ + ∞
= ∞

5. Calculate the slip at maximum internal torque:
Slip (S) = (Ns - N) / Ns
Since N = 0, the slip is maximum when N = 0.

Therefore, the slip at maximum internal torque developed is 0.
Free Test
Community Answer
A 420 V, 6 pole, 50 Hz star connected induction rotor has stator impe...
For maximum slip,
s = 0.1187
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A 420 V, 6 pole, 50 Hz star connected induction rotor has stator impedance of 0.07 + j 0.3 ohms and stand still impedance referred to stator is 0.08 + j 0.37 ohms. If the magnetizing current is neglected, the slip at maximum internal torque developed isa)0.125b)0.233c)0.1187d)0.286Correct answer is option 'C'. Can you explain this answer?
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A 420 V, 6 pole, 50 Hz star connected induction rotor has stator impedance of 0.07 + j 0.3 ohms and stand still impedance referred to stator is 0.08 + j 0.37 ohms. If the magnetizing current is neglected, the slip at maximum internal torque developed isa)0.125b)0.233c)0.1187d)0.286Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 420 V, 6 pole, 50 Hz star connected induction rotor has stator impedance of 0.07 + j 0.3 ohms and stand still impedance referred to stator is 0.08 + j 0.37 ohms. If the magnetizing current is neglected, the slip at maximum internal torque developed isa)0.125b)0.233c)0.1187d)0.286Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 420 V, 6 pole, 50 Hz star connected induction rotor has stator impedance of 0.07 + j 0.3 ohms and stand still impedance referred to stator is 0.08 + j 0.37 ohms. If the magnetizing current is neglected, the slip at maximum internal torque developed isa)0.125b)0.233c)0.1187d)0.286Correct answer is option 'C'. Can you explain this answer?.
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