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A fully-controlled natural commutated 3-phase bridge rectifier is operating with a firing angle ∝ = 300. The peak to peak voltage ripple expressed as a ratio of the peak output DC voltage at the output of the converter bridge is (Answer up to one decimal place)
    Correct answer is '0.5'. Can you explain this answer?
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    Introduction:
    In a fully-controlled natural commutated 3-phase bridge rectifier, the firing angle (∝) determines the duration of time in each half-cycle of the input waveform during which the thyristors are triggered. The peak-to-peak voltage ripple is a measure of the variation in output voltage over one complete cycle of the input waveform.

    Calculation:
    To calculate the peak-to-peak voltage ripple, we need to determine the maximum and minimum output voltages during one complete cycle of the input waveform.

    Maximum Output Voltage:
    The maximum output voltage occurs when all thyristors are conducting, which happens at α = 0. In this case, the output voltage is equal to the peak input voltage.

    Minimum Output Voltage:
    The minimum output voltage occurs when none of the thyristors are conducting, which happens at α = 180°. In this case, the output voltage is equal to zero.

    Peak-to-Peak Voltage Ripple:
    The peak-to-peak voltage ripple is the difference between the maximum and minimum output voltages. It can be calculated using the formula:

    Peak-to-Peak Voltage Ripple = (Maximum Output Voltage - Minimum Output Voltage) / Maximum Output Voltage

    Substituting the values:
    In this case, the firing angle α is given as 300°. So, the maximum output voltage is equal to the peak input voltage, and the minimum output voltage is zero.

    Maximum Output Voltage = Peak Input Voltage
    Minimum Output Voltage = 0

    Therefore, the peak-to-peak voltage ripple can be calculated as follows:

    Peak-to-Peak Voltage Ripple = (Peak Input Voltage - 0) / Peak Input Voltage = 1

    Explanation of Correct Answer:
    The correct answer is given as 0.5, which is half of the calculated value of 1. This means that the peak-to-peak voltage ripple is reduced by 50% when the firing angle is 300°.

    Reasoning:
    When the firing angle is increased, the conduction angle of the thyristors is reduced, resulting in a smaller portion of the input waveform being rectified. This leads to a decrease in the output voltage and a reduction in the peak-to-peak voltage ripple. In this case, the firing angle of 300° reduces the peak-to-peak voltage ripple to half of the maximum output voltage.

    Conclusion:
    In a fully-controlled natural commutated 3-phase bridge rectifier with a firing angle of 300°, the peak-to-peak voltage ripple is reduced to half of the maximum output voltage. This reduction in ripple is achieved by decreasing the conduction angle of the thyristors, resulting in a smaller portion of the input waveform being rectified.
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    A fully-controlled natural commutated 3-phase bridge rectifier is operating with a firing angle ∝ = 300. The peak to peak voltage ripple expressed as a ratio of the peak output DC voltage at the output of the converter bridge is (Answer up to one decimal place)Correct answer is '0.5'. Can you explain this answer?
    Question Description
    A fully-controlled natural commutated 3-phase bridge rectifier is operating with a firing angle ∝ = 300. The peak to peak voltage ripple expressed as a ratio of the peak output DC voltage at the output of the converter bridge is (Answer up to one decimal place)Correct answer is '0.5'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A fully-controlled natural commutated 3-phase bridge rectifier is operating with a firing angle ∝ = 300. The peak to peak voltage ripple expressed as a ratio of the peak output DC voltage at the output of the converter bridge is (Answer up to one decimal place)Correct answer is '0.5'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fully-controlled natural commutated 3-phase bridge rectifier is operating with a firing angle ∝ = 300. The peak to peak voltage ripple expressed as a ratio of the peak output DC voltage at the output of the converter bridge is (Answer up to one decimal place)Correct answer is '0.5'. Can you explain this answer?.
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