In a simple RC high pass filter, the desired roll-off frequency is 15 Hz and C = 10 μF. The value of R (in kΩ) would be ____. (Answer up to two decimal places)Correct answer is '1.06'. Can you explain this answer?

Question

Answer

W_e = 2πf_e = 1/RC

R = (1) / (2π x 15 x 10 x 10^-6) = 1.06kΩ

Answer

Introduction:
A high pass filter is an electronic circuit that allows high-frequency signals to pass through while attenuating low-frequency signals. It is commonly used in audio systems to filter out unwanted low-frequency noise or to emphasize higher frequency components. In a simple RC high pass filter, the cutoff frequency is determined by the values of the resistor (R) and capacitor (C) used in the circuit.

Formula:
The cutoff frequency (fc) of a simple RC high pass filter is given by the formula:
fc = 1 / (2πRC)

Given:
Roll-off frequency (fc) = 15 Hz
Capacitance (C) = 10 μF

Solution:
To find the value of resistor (R) in kΩ, we can rearrange the formula as follows:
R = 1 / (2πfcC)

Step 1: Convert units:
Since the given capacitance is in μF, we need to convert it to Farads (F):
1 μF = 10^-6 F

Step 2: Substitute values:
Substituting the given values into the formula:
R = 1 / (2π * 15 * 10^(-6) * 10^(-3)) [Converting fc to Hz and C to F]

Simplifying the expression:
R = 1 / (2π * 15 * 10^(-9))

Step 3: Calculate:
Using the value of π as 3.14159:
R = 1 / (2 * 3.14159 * 15 * 10^(-9))
R ≈ 1.06 kΩ

Therefore, the value of resistor (R) in the RC high pass filter is approximately 1.06 kΩ, considering two decimal places.

Similar Electronics and Communication Engineering (ECE) Doubts

A white noise signal having two sided spectral density of 5*10-6 V2/Hz is applied to a simple RC low pass filter whose 3 dB cutoff frequency is 5 kHz. The mean squared value of noise obtained at the output of filter would be

A continuous-time signal has frequency content at f = 10 MHz, 50 MHz, and 70 MHz. The signal is sampled at a sampling frequency of 56 MHz and is then passed through a low-pass filter with a cutoff frequency of 15 MHz. The frequency content of the output of the filter will be

A sinusoid x(t) of unknown frequency is sampled by an impulse train of period 20 ms. The resulting sample train is next applied to an ideal lowpass filter with cutoff at 25 Hz. The filter output is seen to be a sinusoid of frequency 20 Hz. This means that x(t) is

A 1.0 kHz signal is flat-top sampled at the rate of 180 samples sec and the samples are applied to an idealrectangular LPF with cat-off frequency of 1100 Hz, then the output of the filter contains

Top Courses for Electronics and Communication Engineering (ECE)View all

GATE ECE (Electronics) Mock Test Series 2025

Network Theory (Electric Circuits)

General Aptitude for GATE

Crash Course: Electronic Communication Engineering (ECE)

Signals and Systems

Top Courses for Electronics and Communication Engineering (ECE)

Top Courses for Electronics and Communication Engineering (ECE)

Suggested Free Tests

Related Content

Mock Test Series

Subject-wise Courses

Subject-wise Courses

Other Engg Branches

Company