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The resultant force acting at a tool point is 1200 N and its angle of inclination to the horizontal is 58°. The plan approach angle to which it acts perpendicularly is 28°. The required feed force to turn the component (in N) is
- a)514
- b)1018
- c)561
- d)299
Correct answer is option 'D'. Can you explain this answer?
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The resultant force acting at a tool point is 1200 N and its angle of...
To find the required feed force to turn the component, we need to resolve the resultant force into its components along the horizontal and vertical directions.
1. Resolve Resultant Force:
The resultant force acting at the tool point is 1200 N and its angle of inclination to the horizontal is 58°. We can resolve this force into horizontal and vertical components using trigonometry.
Vertical Component (Fv) = Resultant Force * sin(angle of inclination)
Fv = 1200 N * sin(58°)
Fv = 1200 N * 0.848
Fv = 1017.6 N
Horizontal Component (Fh) = Resultant Force * cos(angle of inclination)
Fh = 1200 N * cos(58°)
Fh = 1200 N * 0.529
Fh = 635.4 N
2. Find the Plan Approach Force:
The plan approach angle is the angle at which the resultant force acts perpendicular to the surface of the component. In this case, the plan approach angle is given as 28°.
Plan Approach Force (Fa) = Resultant Force * sin(plan approach angle)
Fa = 1200 N * sin(28°)
Fa = 1200 N * 0.469
Fa = 562.8 N
3. Find the Required Feed Force:
The required feed force is the force required to turn the component. It is the horizontal component of the resultant force minus the plan approach force.
Required Feed Force = Horizontal Component - Plan Approach Force
Required Feed Force = 635.4 N - 562.8 N
Required Feed Force = 72.6 N
Therefore, the required feed force to turn the component is 72.6 N. However, none of the given options matches this value. Hence, there may be an error in the given options, and the correct answer cannot be determined with the given information.
1. Resolve Resultant Force:
The resultant force acting at the tool point is 1200 N and its angle of inclination to the horizontal is 58°. We can resolve this force into horizontal and vertical components using trigonometry.
Vertical Component (Fv) = Resultant Force * sin(angle of inclination)
Fv = 1200 N * sin(58°)
Fv = 1200 N * 0.848
Fv = 1017.6 N
Horizontal Component (Fh) = Resultant Force * cos(angle of inclination)
Fh = 1200 N * cos(58°)
Fh = 1200 N * 0.529
Fh = 635.4 N
2. Find the Plan Approach Force:
The plan approach angle is the angle at which the resultant force acts perpendicular to the surface of the component. In this case, the plan approach angle is given as 28°.
Plan Approach Force (Fa) = Resultant Force * sin(plan approach angle)
Fa = 1200 N * sin(28°)
Fa = 1200 N * 0.469
Fa = 562.8 N
3. Find the Required Feed Force:
The required feed force is the force required to turn the component. It is the horizontal component of the resultant force minus the plan approach force.
Required Feed Force = Horizontal Component - Plan Approach Force
Required Feed Force = 635.4 N - 562.8 N
Required Feed Force = 72.6 N
Therefore, the required feed force to turn the component is 72.6 N. However, none of the given options matches this value. Hence, there may be an error in the given options, and the correct answer cannot be determined with the given information.
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Community Answer
The resultant force acting at a tool point is 1200 N and its angle of...
Cutting force, Fc = Fr x sin 58°
= 1200 x sin 58°
= 1017.657 N
Feed force, Fr = Ft x tan 28° ......... (1)
Where Ft = thrust force
Resultant force at a pool point is
Fr2 = Fc2 + Ff2 +Ft2.
(1200)2 = (1017.65)2 + Ft2 x tan2 18° + Ft2
⇒ Ft = 561.469 N
(1) ⇒ Ff = 561.469 x tan 28°
= 298.53 N
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The resultant force acting at a tool point is 1200 N and its angle of inclination to the horizontal is 58°. The plan approach angle to which it acts perpendicularly is 28°. The required feed force to turn the component (in N) isa)514b)1018c)561d)299Correct answer is option 'D'. Can you explain this answer?
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