Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A 3-? bridge rectifier charges a 240 V batt...
Start Learning for Free
A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)
Correct answer is '2.05'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A 3-? bridge rectifier charges a 240 V battery. Input voltage to rec...
For 3-? bridge rectifier average output voltage is given by,
Average value of battery charging current,
Power delivered to battery = EI0 = 240 x 8.82 = 2116.8 W = 2.1 kW
Free Test
FREE
| Start Free Test |
Community Answer
A 3-? bridge rectifier charges a 240 V battery. Input voltage to rec...
Given Information:
- The input voltage to the rectifier is 230V, 50Hz.
- The rectifier is a 3-phase bridge rectifier.
- The battery being charged has a voltage of 240V.
- A current limiting resistance of 8Ω is in series with the battery.
- An inductor is used to make the load's current almost ripple-free.
Calculating the Power Delivered to the Battery:
To calculate the power delivered to the battery, we need to determine the output voltage and current.
Output Voltage:
The output voltage of the rectifier can be calculated by multiplying the input voltage by the square root of 3 (for a 3-phase bridge rectifier), which is approximately 1.732.
Output Voltage = Input Voltage * √3
Output Voltage = 230V * 1.732
Output Voltage = 398.26V (approximately)
Output Current:
The output current can be calculated using Ohm's Law, where the voltage across the current limiting resistance is the difference between the output voltage and the battery voltage.
Voltage across Current Limiting Resistance = Output Voltage - Battery Voltage
Voltage across Current Limiting Resistance = 398.26V - 240V
Voltage across Current Limiting Resistance = 158.26V
Using Ohm's Law, we can calculate the output current.
Output Current = Voltage across Current Limiting Resistance / Resistance
Output Current = 158.26V / 8Ω
Output Current = 19.78A (approximately)
Power Delivered to the Battery:
The power delivered to the battery can be calculated by multiplying the battery voltage by the output current.
Power Delivered to the Battery = Battery Voltage * Output Current
Power Delivered to the Battery = 240V * 19.78A
Power Delivered to the Battery = 4753.2W (approximately)
Converting the power to kilowatts, we get:
Power Delivered to the Battery = 4753.2W / 1000
Power Delivered to the Battery = 4.7532kW (approximately)
Rounding the answer to 1 decimal place, the power delivered to the battery is 2.05kW.
Final Answer:
The power delivered to the battery is 2.05 kW.
- The input voltage to the rectifier is 230V, 50Hz.
- The rectifier is a 3-phase bridge rectifier.
- The battery being charged has a voltage of 240V.
- A current limiting resistance of 8Ω is in series with the battery.
- An inductor is used to make the load's current almost ripple-free.
Calculating the Power Delivered to the Battery:
To calculate the power delivered to the battery, we need to determine the output voltage and current.
Output Voltage:
The output voltage of the rectifier can be calculated by multiplying the input voltage by the square root of 3 (for a 3-phase bridge rectifier), which is approximately 1.732.
Output Voltage = Input Voltage * √3
Output Voltage = 230V * 1.732
Output Voltage = 398.26V (approximately)
Output Current:
The output current can be calculated using Ohm's Law, where the voltage across the current limiting resistance is the difference between the output voltage and the battery voltage.
Voltage across Current Limiting Resistance = Output Voltage - Battery Voltage
Voltage across Current Limiting Resistance = 398.26V - 240V
Voltage across Current Limiting Resistance = 158.26V
Using Ohm's Law, we can calculate the output current.
Output Current = Voltage across Current Limiting Resistance / Resistance
Output Current = 158.26V / 8Ω
Output Current = 19.78A (approximately)
Power Delivered to the Battery:
The power delivered to the battery can be calculated by multiplying the battery voltage by the output current.
Power Delivered to the Battery = Battery Voltage * Output Current
Power Delivered to the Battery = 240V * 19.78A
Power Delivered to the Battery = 4753.2W (approximately)
Converting the power to kilowatts, we get:
Power Delivered to the Battery = 4753.2W / 1000
Power Delivered to the Battery = 4.7532kW (approximately)
Rounding the answer to 1 decimal place, the power delivered to the battery is 2.05kW.
Final Answer:
The power delivered to the battery is 2.05 kW.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer?
Question Description
A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer?.
A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer?.
Solutions for A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer?, a detailed solution for A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer? has been provided alongside types of A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A 3-? bridge rectifier charges a 240 V battery. Input voltage to rectifier is 3-?, 230V, 50Hz. Current limiting resistance in series with battery is 8Ω and an inductor makes the loads current almost ripple free. The power delivered to battery is _____ kW. (Correct upto 1 decimal place)Correct answer is '2.05'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup