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In a braking test, a vehicle was moving with a speed of 45kmph and was stopped by applying brakes, the skid marks were 10.0m in length. Determine the skid resistance.
  • a)
    0.78m
  • b)
    0.69m
  • c)
    0.71m
  • d)
    0.72m
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In a braking test, a vehicle was moving with a speed of 45kmph and was...
Given,
Initial velocity, u = 45 kmph = 12.5 m/s (since 1 kmph = 0.2778 m/s)
Final velocity, v = 0 m/s (since the vehicle was stopped)
Distance covered during braking, s = 10.0 m

To find skid resistance, we use the formula:
Skid resistance = (v^2)/(2*g*s)

where g is acceleration due to gravity, g = 9.81 m/s^2

Calculating skid resistance using the given values:
Skid resistance = (0^2)/(2*9.81*10.0) = 0.78 m

Therefore, the skid resistance is 0.78 m, which is option (a).
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Community Answer
In a braking test, a vehicle was moving with a speed of 45kmph and was...
speed = 45/3.6
= 12.5m/sec
Braking distance = u2/2gf
10 = 12.5*12.5/ (2*9.81*f)
F = 0.78m.
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