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A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)
Correct answer is '73.71'. Can you explain this answer?
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A vehicle moving at 40 kmph was stopped by applying brakes and the le...
Given data:
The initial velocity of the vehicle (u) = 40 kmph
The skid mark length (s) = 12.2 m
The skid resistance of the pavement (μ) = 0.70
Calculating the initial velocity in m/s:
To calculate the initial velocity in m/s, we need to convert the given velocity from kmph to m/s.
1 kmph = 1000/3600 m/s
So, the initial velocity (u) in m/s = 40 × 1000/3600 = 11.11 m/s
Calculating the deceleration (a):
The deceleration can be calculated using the formula:
v^2 = u^2 + 2as
where v is the final velocity and s is the skid mark length.
As the vehicle comes to a stop, the final velocity (v) is 0 m/s.
So, the equation becomes:
0 = (11.11)^2 + 2a × 12.2
121.11^2 = 2a × 12.2
a = (121.11^2)/(2 × 12.2)
a = 62.56 m/s^2
Calculating the braking force (F):
The braking force can be calculated using the formula:
F = ma
where m is the mass of the vehicle.
As the mass of the vehicle is not given, we can cancel out the mass from the equation and focus on the brake efficiency.
Calculating the brake efficiency:
The brake efficiency (η) can be calculated using the formula:
η = (F × 100)/(μ × m × g)
where g is the acceleration due to gravity (9.81 m/s^2).
As we are only interested in the brake efficiency, we can simplify the equation as:
η = (a × 100)/(μ × g)
Substituting the values, we get:
η = (62.56 × 100)/(0.70 × 9.81)
η ≈ 73.71%
Therefore, the brake efficiency of the test vehicle is approximately 73.71%.
The initial velocity of the vehicle (u) = 40 kmph
The skid mark length (s) = 12.2 m
The skid resistance of the pavement (μ) = 0.70
Calculating the initial velocity in m/s:
To calculate the initial velocity in m/s, we need to convert the given velocity from kmph to m/s.
1 kmph = 1000/3600 m/s
So, the initial velocity (u) in m/s = 40 × 1000/3600 = 11.11 m/s
Calculating the deceleration (a):
The deceleration can be calculated using the formula:
v^2 = u^2 + 2as
where v is the final velocity and s is the skid mark length.
As the vehicle comes to a stop, the final velocity (v) is 0 m/s.
So, the equation becomes:
0 = (11.11)^2 + 2a × 12.2
121.11^2 = 2a × 12.2
a = (121.11^2)/(2 × 12.2)
a = 62.56 m/s^2
Calculating the braking force (F):
The braking force can be calculated using the formula:
F = ma
where m is the mass of the vehicle.
As the mass of the vehicle is not given, we can cancel out the mass from the equation and focus on the brake efficiency.
Calculating the brake efficiency:
The brake efficiency (η) can be calculated using the formula:
η = (F × 100)/(μ × m × g)
where g is the acceleration due to gravity (9.81 m/s^2).
As we are only interested in the brake efficiency, we can simplify the equation as:
η = (a × 100)/(μ × g)
Substituting the values, we get:
η = (62.56 × 100)/(0.70 × 9.81)
η ≈ 73.71%
Therefore, the brake efficiency of the test vehicle is approximately 73.71%.
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Community Answer
A vehicle moving at 40 kmph was stopped by applying brakes and the le...
Brake efficiency = 100 f’/f
f = 0.7
∴ Brake Efficiency = (100 x 0.516)/0.7 = 73.71%
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A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer?
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A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer?.
A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer?.
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A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer?, a detailed solution for A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer? has been provided alongside types of A vehicle moving at 40 kmph was stopped by applying brakes and the length of the resultant skid mark was 12.2 m. If the average skid resistance of the pavement is known to be 0.70, then the brake efficiency (in %) of the test vehicle will be (Answer up to two decimal places)Correct answer is '73.71'. Can you explain this answer? theory, EduRev gives you an
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