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A 16 bit computer can address 1M word and has 128K words installed from 64K x 1 chips. Calculate the no. of chips required and no. of bits of address bus that allows to select the memory chips
  • a)
    16 and 1
  • b)
    32 and 1
  • c)
    16 and 2
  • d)
    32 and 2
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A 16 bit computer can address 1M word and has 128K words installed fr...
To determine the number of chips required and the number of bits of the address bus that allows selecting the memory chips, we need to consider the given information.

Given:
- The computer is 16-bit, which means it can address 2^16 (64K) words.
- The computer has 128K words of installed memory.
- The memory chips are 64K x 1 (64K words with 1-bit output).

1. Calculate the Number of Chips Required:
To calculate the number of chips required, divide the total number of installed words by the number of words per chip.

Installed Words = 128K
Words per Chip = 64K

Number of Chips Required = Installed Words / Words per Chip
= 128K / 64K
= 2

Therefore, the number of chips required is 2.

2. Calculate the Number of Bits of Address Bus:
To calculate the number of bits of the address bus, we need to find the number of bits required to address the installed memory.

Installed Memory = 128K words
Addressable Memory = 64K words (16-bit computer)

Number of Address Bits = log2(Addressable Memory)
= log2(64K)
= log2(2^16)
= 16 bits

Therefore, the number of bits of the address bus required to select the memory chips is 16 bits.

So, based on the given options:
a) 16 and 1: This option does not match the calculated values.
b) 32 and 1: This option matches the calculated values.
c) 16 and 2: This option does not match the calculated values.
d) 32 and 2: This option does not match the calculated values.

Hence, the correct answer is option 'B' - 32 and 1. This option corresponds to the calculated values of 2 chips required and 16 bits of the address bus.
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Community Answer
A 16 bit computer can address 1M word and has 128K words installed fr...
As it is a 64K memory chips hence 16 bits are needed to address them
i.e. 64K = 216
As we want 128K × 16 from 64K × 1 chips
No. of chips = 128K×16/64K×1 = 32
Now as we have two rows of 16 chips each, we will need 1 bit to difference one row from another. So A16 will be used to select the memory chips
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A 16 bit computer can address 1M word and has 128K words installed from 64K x 1 chips. Calculate the no. of chips required and no. of bits of address bus that allows to select the memory chipsa)16 and 1b)32 and 1c)16 and 2d)32 and 2Correct answer is option 'B'. Can you explain this answer?
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