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In an orthogonal cutting test, the cutting force and thrust force were observed to the 1000 N and 500 N respectively. If the rake angle of tool is zero, the coefficient of friction in chip-tool interface will be
  • a)
    1/2
  • b)
    2
  • c)
    1/√2
  • d)
    √2
Correct answer is option 'A'. Can you explain this answer?
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Orthogonal Cutting Test and Coefficient of Friction

Introduction:
In orthogonal cutting, a cutting tool with a zero rake angle is used to remove material from a workpiece. This test is conducted to study the cutting forces involved in the process. The cutting force and thrust force are observed during the test. The coefficient of friction in the chip-tool interface can be determined using these forces.

Given Information:
- Cutting force = 1000 N
- Thrust force = 500 N
- Rake angle of the tool = 0

Calculating the Coefficient of Friction:
The coefficient of friction (μ) can be calculated using the formula:

μ = (Thrust force)/(Cutting force)

Given that the thrust force is 500 N and the cutting force is 1000 N, we can substitute these values into the formula:

μ = 500 N / 1000 N = 0.5

Therefore, the coefficient of friction in the chip-tool interface is 0.5.

Explanation:
The coefficient of friction is a measure of the resistance to sliding between two surfaces in contact. In the context of orthogonal cutting, it represents the friction between the chip and the tool. A coefficient of friction of 0.5 indicates that there is moderate friction between the chip and the tool.

Conclusion:
To summarize, in an orthogonal cutting test with a zero rake angle, if the cutting force is 1000 N and the thrust force is 500 N, the coefficient of friction in the chip-tool interface is 0.5. This coefficient of friction represents the moderate level of friction between the chip and the tool.
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