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The total passive earth pressure per unit length (in t/m) against a retaining of height 3 m with back fill of unit weight 1.8 t/m3 and angle of internal friction 30° will be (Answer up to one decimal place)
Correct answer is '24.3'. Can you explain this answer?
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The total passive earth pressure per unit length (in t/m) against a r...
Given data:
- Height of the retaining wall (H) = 3 m
- Unit weight of the backfill soil (γ) = 1.8 t/m^3
- Angle of internal friction (φ) = 30°
Calculating the total passive earth pressure:
The total passive earth pressure can be calculated using the Rankine's theory of earth pressure. According to this theory, the total passive earth pressure (P) can be given by the equation:
P = 0.5 * γ * H^2 * tan^2(45 + φ/2)
Here, γ is the unit weight of the backfill soil and H is the height of the retaining wall. φ is the angle of internal friction.
Substituting the given values into the equation:
P = 0.5 * 1.8 * 3^2 * tan^2(45 + 30/2)
P = 0.5 * 1.8 * 9 * tan^2(45 + 15)
P = 0.9 * 9 * tan^2(60)
P = 8.1 * tan^2(60)
P = 8.1 * (√3)^2
P = 8.1 * 3
P = 24.3 t/m
Answer:
The total passive earth pressure per unit length against the retaining wall will be 24.3 t/m.
- Height of the retaining wall (H) = 3 m
- Unit weight of the backfill soil (γ) = 1.8 t/m^3
- Angle of internal friction (φ) = 30°
Calculating the total passive earth pressure:
The total passive earth pressure can be calculated using the Rankine's theory of earth pressure. According to this theory, the total passive earth pressure (P) can be given by the equation:
P = 0.5 * γ * H^2 * tan^2(45 + φ/2)
Here, γ is the unit weight of the backfill soil and H is the height of the retaining wall. φ is the angle of internal friction.
Substituting the given values into the equation:
P = 0.5 * 1.8 * 3^2 * tan^2(45 + 30/2)
P = 0.5 * 1.8 * 9 * tan^2(45 + 15)
P = 0.9 * 9 * tan^2(60)
P = 8.1 * tan^2(60)
P = 8.1 * (√3)^2
P = 8.1 * 3
P = 24.3 t/m
Answer:
The total passive earth pressure per unit length against the retaining wall will be 24.3 t/m.
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Community Answer
The total passive earth pressure per unit length (in t/m) against a r...
Pp = 1/2 × 3 × 1.8 × 32 = 24.3 t/m
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The total passive earth pressure per unit length (in t/m) against a retaining of height 3 m with back fill of unit weight 1.8 t/m3 and angle of internal friction 30° will be (Answer up to one decimal place)Correct answer is '24.3'. Can you explain this answer?
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The total passive earth pressure per unit length (in t/m) against a retaining of height 3 m with back fill of unit weight 1.8 t/m3 and angle of internal friction 30° will be (Answer up to one decimal place)Correct answer is '24.3'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The total passive earth pressure per unit length (in t/m) against a retaining of height 3 m with back fill of unit weight 1.8 t/m3 and angle of internal friction 30° will be (Answer up to one decimal place)Correct answer is '24.3'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The total passive earth pressure per unit length (in t/m) against a retaining of height 3 m with back fill of unit weight 1.8 t/m3 and angle of internal friction 30° will be (Answer up to one decimal place)Correct answer is '24.3'. Can you explain this answer?.
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