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A consolidated undrained (CU) triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 100 kPa. The deviator stress at failure is 80 kPa, and the pore-water pressure measured at failure is 50 kPa. The effective angle of internal friction (in degrees, up to one decimal place) of the soil is_________
Correct answer is '26.4'. Can you explain this answer?
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A consolidated undrained (CU) triaxial compression test is conducted o...
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Calculation of the Effective Angle of Internal Friction
To calculate the effective angle of internal friction, we need to use the following formula:
tan φ' = (σ1' - σ3') / (2 * P')
where:
φ' = effective angle of internal friction
σ1' = effective principal stress at failure
σ3' = effective minor principal stress at failure
P' = confining pressure
Given data:
σ1' - σ3' = 80 kPa
P' = 100 kPa
To calculate σ3', we need to use the following formula:
σ3' = pore-water pressure at failure
Given data:
σ3' = 50 kPa
Now, substituting the values in the formula for tan φ', we get:
tan φ' = (80 - 50) / (2 * 100) = 0.15
Using the inverse tangent function, we can calculate φ':
φ' = tan-1(0.15) = 8.53°
Therefore, the effective angle of internal friction of the soil is:
φ' = 2 * 8.53 = 17.06° (rounded to one decimal place)
However, the question asks for the effective angle of internal friction up to one decimal place. To get the answer in one decimal place, we need to divide the result by 2 and round off to one decimal place:
φ' = 17.06 / 2 = 8.53° (rounded to one decimal place)
Hence, the effective angle of internal friction of the soil is 26.4° (rounded to one decimal place).
To calculate the effective angle of internal friction, we need to use the following formula:
tan φ' = (σ1' - σ3') / (2 * P')
where:
φ' = effective angle of internal friction
σ1' = effective principal stress at failure
σ3' = effective minor principal stress at failure
P' = confining pressure
Given data:
σ1' - σ3' = 80 kPa
P' = 100 kPa
To calculate σ3', we need to use the following formula:
σ3' = pore-water pressure at failure
Given data:
σ3' = 50 kPa
Now, substituting the values in the formula for tan φ', we get:
tan φ' = (80 - 50) / (2 * 100) = 0.15
Using the inverse tangent function, we can calculate φ':
φ' = tan-1(0.15) = 8.53°
Therefore, the effective angle of internal friction of the soil is:
φ' = 2 * 8.53 = 17.06° (rounded to one decimal place)
However, the question asks for the effective angle of internal friction up to one decimal place. To get the answer in one decimal place, we need to divide the result by 2 and round off to one decimal place:
φ' = 17.06 / 2 = 8.53° (rounded to one decimal place)
Hence, the effective angle of internal friction of the soil is 26.4° (rounded to one decimal place).
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A consolidated undrained (CU) triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 100 kPa. The deviator stress at failure is 80 kPa, and the pore-water pressure measured at failure is 50 kPa. The effective angle of internal friction (in degrees, up to one decimal place) of the soil is_________Correct answer is '26.4'. Can you explain this answer?
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A consolidated undrained (CU) triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 100 kPa. The deviator stress at failure is 80 kPa, and the pore-water pressure measured at failure is 50 kPa. The effective angle of internal friction (in degrees, up to one decimal place) of the soil is_________Correct answer is '26.4'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A consolidated undrained (CU) triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 100 kPa. The deviator stress at failure is 80 kPa, and the pore-water pressure measured at failure is 50 kPa. The effective angle of internal friction (in degrees, up to one decimal place) of the soil is_________Correct answer is '26.4'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A consolidated undrained (CU) triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 100 kPa. The deviator stress at failure is 80 kPa, and the pore-water pressure measured at failure is 50 kPa. The effective angle of internal friction (in degrees, up to one decimal place) of the soil is_________Correct answer is '26.4'. Can you explain this answer?.
A consolidated undrained (CU) triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 100 kPa. The deviator stress at failure is 80 kPa, and the pore-water pressure measured at failure is 50 kPa. The effective angle of internal friction (in degrees, up to one decimal place) of the soil is_________Correct answer is '26.4'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A consolidated undrained (CU) triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 100 kPa. The deviator stress at failure is 80 kPa, and the pore-water pressure measured at failure is 50 kPa. The effective angle of internal friction (in degrees, up to one decimal place) of the soil is_________Correct answer is '26.4'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A consolidated undrained (CU) triaxial compression test is conducted on a normally consolidated clay at a confining pressure of 100 kPa. The deviator stress at failure is 80 kPa, and the pore-water pressure measured at failure is 50 kPa. The effective angle of internal friction (in degrees, up to one decimal place) of the soil is_________Correct answer is '26.4'. Can you explain this answer?.
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