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A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. The ultimate tensile strength of the material of the shaft is 600 MPa and yield stress of the material is 450 MPa. Correction for type of loading is 0.6, size factor is 0.85, surface finish factor is 0.8 and stress concentration factor is 1.2. What will be the diameter of the shaft (in mm) for an infinite life for a factor of safety of 1.8? (to the next integer)
Correct answer is '38'. Can you explain this answer?
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A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. ...
To determine the diameter of the shaft, we need to consider the given torque range, material strength properties, and various correction factors. The following steps explain how to calculate the diameter:
1. Calculate the mean torque:
Mean Torque = (Maximum Torque + Minimum Torque) / 2
Mean Torque = (800 N-m + 1200 N-m) / 2
Mean Torque = 1000 N-m
2. Determine the allowable stress:
Allowable Stress = Ultimate Tensile Strength / Factor of Safety
Allowable Stress = 600 MPa / 1.8
Allowable Stress = 333.33 MPa
3. Apply the correction factors:
Corrected Stress = Allowable Stress * Type of Loading * Size Factor * Surface Finish Factor * Stress Concentration Factor
Corrected Stress = 333.33 MPa * 0.6 * 0.85 * 0.8 * 1.2
Corrected Stress = 136.96 MPa
4. Calculate the diameter:
Diameter = sqrt((16 * Torque) / (pi * Corrected Stress))
Diameter = sqrt((16 * 1000 N-m) / (pi * 136.96 MPa))
Diameter = sqrt(11.62)
Diameter = 3.41 mm
Since the given answer is '38', it seems there may be an error in the given information or calculations. The calculated diameter is significantly smaller than the expected answer. Please double-check the question or provide additional information for further analysis.
1. Calculate the mean torque:
Mean Torque = (Maximum Torque + Minimum Torque) / 2
Mean Torque = (800 N-m + 1200 N-m) / 2
Mean Torque = 1000 N-m
2. Determine the allowable stress:
Allowable Stress = Ultimate Tensile Strength / Factor of Safety
Allowable Stress = 600 MPa / 1.8
Allowable Stress = 333.33 MPa
3. Apply the correction factors:
Corrected Stress = Allowable Stress * Type of Loading * Size Factor * Surface Finish Factor * Stress Concentration Factor
Corrected Stress = 333.33 MPa * 0.6 * 0.85 * 0.8 * 1.2
Corrected Stress = 136.96 MPa
4. Calculate the diameter:
Diameter = sqrt((16 * Torque) / (pi * Corrected Stress))
Diameter = sqrt((16 * 1000 N-m) / (pi * 136.96 MPa))
Diameter = sqrt(11.62)
Diameter = 3.41 mm
Since the given answer is '38', it seems there may be an error in the given information or calculations. The calculated diameter is significantly smaller than the expected answer. Please double-check the question or provide additional information for further analysis.
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Community Answer
A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. ...
Mean torque, 
Variable torque, 
Endurance limit for reversed bending,
Se = 0.5 Sut = 0.5 600 = 300 MPa
Yield strength in shear,
Sy.s = 0.6 Sy.t = 0.6 450 = 270 MPa
Let d be the diameter of the solid shaft.
Mean stress, 
Variable stress ,
A, correction for type of loading, is taken as 0.6; B, size factor, is taken as 0.85; and C, surface finish factor, is taken as 0.8.
According to Soderberg formula,
On simplification, d = 38 mm
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A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. The ultimate tensile strength of the material of the shaft is 600 MPa and yield stress of the material is 450 MPa. Correction for type of loading is 0.6, size factor is 0.85, surface finish factor is 0.8 and stress concentration factor is 1.2. What will be the diameter of the shaft (in mm) for an infinite life for a factor of safety of 1.8? (to the next integer)Correct answer is '38'. Can you explain this answer?
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A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. The ultimate tensile strength of the material of the shaft is 600 MPa and yield stress of the material is 450 MPa. Correction for type of loading is 0.6, size factor is 0.85, surface finish factor is 0.8 and stress concentration factor is 1.2. What will be the diameter of the shaft (in mm) for an infinite life for a factor of safety of 1.8? (to the next integer)Correct answer is '38'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. The ultimate tensile strength of the material of the shaft is 600 MPa and yield stress of the material is 450 MPa. Correction for type of loading is 0.6, size factor is 0.85, surface finish factor is 0.8 and stress concentration factor is 1.2. What will be the diameter of the shaft (in mm) for an infinite life for a factor of safety of 1.8? (to the next integer)Correct answer is '38'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. The ultimate tensile strength of the material of the shaft is 600 MPa and yield stress of the material is 450 MPa. Correction for type of loading is 0.6, size factor is 0.85, surface finish factor is 0.8 and stress concentration factor is 1.2. What will be the diameter of the shaft (in mm) for an infinite life for a factor of safety of 1.8? (to the next integer)Correct answer is '38'. Can you explain this answer?.
A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. The ultimate tensile strength of the material of the shaft is 600 MPa and yield stress of the material is 450 MPa. Correction for type of loading is 0.6, size factor is 0.85, surface finish factor is 0.8 and stress concentration factor is 1.2. What will be the diameter of the shaft (in mm) for an infinite life for a factor of safety of 1.8? (to the next integer)Correct answer is '38'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. The ultimate tensile strength of the material of the shaft is 600 MPa and yield stress of the material is 450 MPa. Correction for type of loading is 0.6, size factor is 0.85, surface finish factor is 0.8 and stress concentration factor is 1.2. What will be the diameter of the shaft (in mm) for an infinite life for a factor of safety of 1.8? (to the next integer)Correct answer is '38'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. The ultimate tensile strength of the material of the shaft is 600 MPa and yield stress of the material is 450 MPa. Correction for type of loading is 0.6, size factor is 0.85, surface finish factor is 0.8 and stress concentration factor is 1.2. What will be the diameter of the shaft (in mm) for an infinite life for a factor of safety of 1.8? (to the next integer)Correct answer is '38'. Can you explain this answer?.
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ample number of questions to practice A stepped shaft transmits a torque varying from 800 N-m to 1200 N-m. The ultimate tensile strength of the material of the shaft is 600 MPa and yield stress of the material is 450 MPa. Correction for type of loading is 0.6, size factor is 0.85, surface finish factor is 0.8 and stress concentration factor is 1.2. What will be the diameter of the shaft (in mm) for an infinite life for a factor of safety of 1.8? (to the next integer)Correct answer is '38'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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