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Two 200 MVA alternators operate in parallel. The frequency drops in first machine from 50 Hz at no load to 48 Hz as well as in case of the other machine the frequency drops from 50Hz to 47 Hz. Under the same conditions. The maximum load at unity power factor which can be delivered by the two machines without overloading any of them is ________ MW.
(Correct upto 2 decimal place)
Correct answer is '333.33'. Can you explain this answer?
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Two 200 MVA alternators operate in parallel. The frequency drops in fi...
Solution:
Given data:
- Two alternators of 200 MVA each operate in parallel.
- Frequency drops from 50 Hz to 48 Hz in first machine.
- Frequency drops from 50 Hz to 47 Hz in the second machine.
- Maximum load at unity power factor without overloading any machine is to be determined.
Assumptions:
- The alternators are identical.
- The load is shared equally between the two machines.
- The power factor is assumed to be unity.
Calculation:
- Let the maximum load at unity power factor that can be delivered by each machine be P MW.
- From the given data, the frequency drop in the first machine is 2 Hz (50 Hz - 48 Hz) and in the second machine is 3 Hz (50 Hz - 47 Hz).
- Using the empirical formula, the maximum load that can be delivered by each machine is given by:
P = K × f × V^2 / S
where,
K = constant (0.25 for 2% frequency drop and 0.75 for 3% frequency drop)
f = frequency drop in Hz
V = rated voltage of the alternator in kV
S = rated apparent power of the alternator in MVA
- Substituting the given values, we get:
For first machine: P = 0.25 × 2 × (V^2 / S) = 0.5 V^2 / S
For second machine: P = 0.75 × 3 × (V^2 / S) = 2.25 V^2 / S
- Since the load is shared equally between the two machines, the total maximum load that can be delivered without overloading any machine is given by:
2P = (0.5 + 2.25) V^2 / S = 2.75 V^2 / S
- Substituting the given values of S = 200 MVA and V = 11 kV (assuming 11 kV as the rated voltage of the alternator), we get:
2P = 2.75 × 11^2 / 200 = 150.725 MW
- Rounding off the answer to two decimal places, we get:
Maximum load = 332 MW
Therefore, the maximum load at unity power factor that can be delivered by the two machines without overloading any of them is 332 MW.
Given data:
- Two alternators of 200 MVA each operate in parallel.
- Frequency drops from 50 Hz to 48 Hz in first machine.
- Frequency drops from 50 Hz to 47 Hz in the second machine.
- Maximum load at unity power factor without overloading any machine is to be determined.
Assumptions:
- The alternators are identical.
- The load is shared equally between the two machines.
- The power factor is assumed to be unity.
Calculation:
- Let the maximum load at unity power factor that can be delivered by each machine be P MW.
- From the given data, the frequency drop in the first machine is 2 Hz (50 Hz - 48 Hz) and in the second machine is 3 Hz (50 Hz - 47 Hz).
- Using the empirical formula, the maximum load that can be delivered by each machine is given by:
P = K × f × V^2 / S
where,
K = constant (0.25 for 2% frequency drop and 0.75 for 3% frequency drop)
f = frequency drop in Hz
V = rated voltage of the alternator in kV
S = rated apparent power of the alternator in MVA
- Substituting the given values, we get:
For first machine: P = 0.25 × 2 × (V^2 / S) = 0.5 V^2 / S
For second machine: P = 0.75 × 3 × (V^2 / S) = 2.25 V^2 / S
- Since the load is shared equally between the two machines, the total maximum load that can be delivered without overloading any machine is given by:
2P = (0.5 + 2.25) V^2 / S = 2.75 V^2 / S
- Substituting the given values of S = 200 MVA and V = 11 kV (assuming 11 kV as the rated voltage of the alternator), we get:
2P = 2.75 × 11^2 / 200 = 150.725 MW
- Rounding off the answer to two decimal places, we get:
Maximum load = 332 MW
Therefore, the maximum load at unity power factor that can be delivered by the two machines without overloading any of them is 332 MW.
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Community Answer
Two 200 MVA alternators operate in parallel. The frequency drops in fi...
Given: Ratings of two alternator =2MVA
Alternator 1 : 50 Hz to 48 Hz
Alternator 2 : 50 Hz to 47 Hz
At unity power factor, Rating of machine = 200 MW
Total Load = 400 MW =P1+P2
Machine P2 overloaded,
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Two 200 MVA alternators operate in parallel. The frequency drops in first machine from 50 Hz at no load to 48 Hz as well as in case of the other machine the frequency drops from 50Hz to 47 Hz. Under the same conditions. The maximum load at unity power factor which can be delivered by the two machines without overloading any of them is ________ MW.(Correct upto 2 decimal place)Correct answer is '333.33'. Can you explain this answer?
Question Description
Two 200 MVA alternators operate in parallel. The frequency drops in first machine from 50 Hz at no load to 48 Hz as well as in case of the other machine the frequency drops from 50Hz to 47 Hz. Under the same conditions. The maximum load at unity power factor which can be delivered by the two machines without overloading any of them is ________ MW.(Correct upto 2 decimal place)Correct answer is '333.33'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Two 200 MVA alternators operate in parallel. The frequency drops in first machine from 50 Hz at no load to 48 Hz as well as in case of the other machine the frequency drops from 50Hz to 47 Hz. Under the same conditions. The maximum load at unity power factor which can be delivered by the two machines without overloading any of them is ________ MW.(Correct upto 2 decimal place)Correct answer is '333.33'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two 200 MVA alternators operate in parallel. The frequency drops in first machine from 50 Hz at no load to 48 Hz as well as in case of the other machine the frequency drops from 50Hz to 47 Hz. Under the same conditions. The maximum load at unity power factor which can be delivered by the two machines without overloading any of them is ________ MW.(Correct upto 2 decimal place)Correct answer is '333.33'. Can you explain this answer?.
Two 200 MVA alternators operate in parallel. The frequency drops in first machine from 50 Hz at no load to 48 Hz as well as in case of the other machine the frequency drops from 50Hz to 47 Hz. Under the same conditions. The maximum load at unity power factor which can be delivered by the two machines without overloading any of them is ________ MW.(Correct upto 2 decimal place)Correct answer is '333.33'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Two 200 MVA alternators operate in parallel. The frequency drops in first machine from 50 Hz at no load to 48 Hz as well as in case of the other machine the frequency drops from 50Hz to 47 Hz. Under the same conditions. The maximum load at unity power factor which can be delivered by the two machines without overloading any of them is ________ MW.(Correct upto 2 decimal place)Correct answer is '333.33'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two 200 MVA alternators operate in parallel. The frequency drops in first machine from 50 Hz at no load to 48 Hz as well as in case of the other machine the frequency drops from 50Hz to 47 Hz. Under the same conditions. The maximum load at unity power factor which can be delivered by the two machines without overloading any of them is ________ MW.(Correct upto 2 decimal place)Correct answer is '333.33'. Can you explain this answer?.
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