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Consider two systems S and R connected by routers serially, Let R0, R1, R2, R3,…R6 be the intermediate routers connected serially between S and R where R0 is connected with S and R1 and R6 is connected with R and R5. If data is transferred from S to R with the time to live at S as (00010011)2 then what is the time to live at R in binary number system? Note: Ignore leading 0′s in the answer?
- a)1011
- b)1012
- c)1001
- d)1031
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Consider two systems S and R connected by routers serially, Let R0, R1...
And R4 be the routers in the network. The system S is connected to R0, R0 is connected to R1, R1 is connected to R2, R2 is connected to R3, and R3 is connected to R4.
To send a packet from S to R4, the packet will pass through each router in the network, starting from R0, then R1, R2, R3, and finally reaching R4.
The process of sending the packet from S to R4 involves several steps:
1. S sends the packet to R0: The packet is generated by S and sent to R0 through a physical link or a network connection.
2. R0 receives the packet: R0 receives the packet from S and processes it. It checks the destination address of the packet to determine the next hop.
3. R0 forwards the packet to R1: R0 forwards the packet to R1 based on the routing table, which contains information about the network topology and the next hop for each destination address. R1 is the next hop for R0 to reach R4.
4. R1 receives the packet: R1 receives the packet from R0 and processes it. It checks the destination address to determine the next hop.
5. R1 forwards the packet to R2: R1 forwards the packet to R2 based on its routing table. R2 is the next hop for R1 to reach R4.
6. R2 receives the packet: R2 receives the packet from R1 and processes it. It checks the destination address to determine the next hop.
7. R2 forwards the packet to R3: R2 forwards the packet to R3 based on its routing table. R3 is the next hop for R2 to reach R4.
8. R3 receives the packet: R3 receives the packet from R2 and processes it. It checks the destination address to determine the next hop.
9. R3 forwards the packet to R4: R3 forwards the packet to R4 based on its routing table. R4 is the final destination for the packet.
10. R4 receives the packet: R4 receives the packet from R3 and processes it. It checks the destination address and delivers the packet to the destination system.
In summary, the packet travels from S to R4 through each router in the network, with each router forwarding the packet to the next hop based on its routing table.
To send a packet from S to R4, the packet will pass through each router in the network, starting from R0, then R1, R2, R3, and finally reaching R4.
The process of sending the packet from S to R4 involves several steps:
1. S sends the packet to R0: The packet is generated by S and sent to R0 through a physical link or a network connection.
2. R0 receives the packet: R0 receives the packet from S and processes it. It checks the destination address of the packet to determine the next hop.
3. R0 forwards the packet to R1: R0 forwards the packet to R1 based on the routing table, which contains information about the network topology and the next hop for each destination address. R1 is the next hop for R0 to reach R4.
4. R1 receives the packet: R1 receives the packet from R0 and processes it. It checks the destination address to determine the next hop.
5. R1 forwards the packet to R2: R1 forwards the packet to R2 based on its routing table. R2 is the next hop for R1 to reach R4.
6. R2 receives the packet: R2 receives the packet from R1 and processes it. It checks the destination address to determine the next hop.
7. R2 forwards the packet to R3: R2 forwards the packet to R3 based on its routing table. R3 is the next hop for R2 to reach R4.
8. R3 receives the packet: R3 receives the packet from R2 and processes it. It checks the destination address to determine the next hop.
9. R3 forwards the packet to R4: R3 forwards the packet to R4 based on its routing table. R4 is the final destination for the packet.
10. R4 receives the packet: R4 receives the packet from R3 and processes it. It checks the destination address and delivers the packet to the destination system.
In summary, the packet travels from S to R4 through each router in the network, with each router forwarding the packet to the next hop based on its routing table.
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Community Answer
Consider two systems S and R connected by routers serially, Let R0, R1...
TTL (Time to Live) is present in IPv4 header and the IP protocol is present in the Network layer. So, devices that have access at least up to the network layer can decrement the value of TTL.
Time to Live at S= (00010011)2 = 19
Time to Live is 8 bits field present in IPv4 header.
TTL is a mechanism that limits the lifespan of a packet in a computer network.
TTL prevents a data packet from circulating indefinitely which is present in IPv4 header.
Every host (operates at the network layer) that passes the packet must reduce the TTL by at least one unit.
Routers can view the TTL field and decrease its value of it when a packet is passed through it. There are 7 routers and 1 receivers. Therefore, the final value of TTL = 19 − 8
= (11)10
= (00001011)2
= (1011)2
Hence, the correct option is (A).
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Consider two systems S and R connected by routers serially, Let R0, R1, R2, R3,…R6 be the intermediate routers connected serially between S and R where R0 is connected with S and R1 and R6 is connected with R and R5. If data is transferred from S to R with the time to live at S as (00010011)2 then what is the time to live at R in binary number system? Note: Ignore leading 0′s in the answer?a)1011b)1012c)1001d)1031Correct answer is option 'A'. Can you explain this answer?
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Consider two systems S and R connected by routers serially, Let R0, R1, R2, R3,…R6 be the intermediate routers connected serially between S and R where R0 is connected with S and R1 and R6 is connected with R and R5. If data is transferred from S to R with the time to live at S as (00010011)2 then what is the time to live at R in binary number system? Note: Ignore leading 0′s in the answer?a)1011b)1012c)1001d)1031Correct answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider two systems S and R connected by routers serially, Let R0, R1, R2, R3,…R6 be the intermediate routers connected serially between S and R where R0 is connected with S and R1 and R6 is connected with R and R5. If data is transferred from S to R with the time to live at S as (00010011)2 then what is the time to live at R in binary number system? Note: Ignore leading 0′s in the answer?a)1011b)1012c)1001d)1031Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider two systems S and R connected by routers serially, Let R0, R1, R2, R3,…R6 be the intermediate routers connected serially between S and R where R0 is connected with S and R1 and R6 is connected with R and R5. If data is transferred from S to R with the time to live at S as (00010011)2 then what is the time to live at R in binary number system? Note: Ignore leading 0′s in the answer?a)1011b)1012c)1001d)1031Correct answer is option 'A'. Can you explain this answer?.
Consider two systems S and R connected by routers serially, Let R0, R1, R2, R3,…R6 be the intermediate routers connected serially between S and R where R0 is connected with S and R1 and R6 is connected with R and R5. If data is transferred from S to R with the time to live at S as (00010011)2 then what is the time to live at R in binary number system? Note: Ignore leading 0′s in the answer?a)1011b)1012c)1001d)1031Correct answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider two systems S and R connected by routers serially, Let R0, R1, R2, R3,…R6 be the intermediate routers connected serially between S and R where R0 is connected with S and R1 and R6 is connected with R and R5. If data is transferred from S to R with the time to live at S as (00010011)2 then what is the time to live at R in binary number system? Note: Ignore leading 0′s in the answer?a)1011b)1012c)1001d)1031Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider two systems S and R connected by routers serially, Let R0, R1, R2, R3,…R6 be the intermediate routers connected serially between S and R where R0 is connected with S and R1 and R6 is connected with R and R5. If data is transferred from S to R with the time to live at S as (00010011)2 then what is the time to live at R in binary number system? Note: Ignore leading 0′s in the answer?a)1011b)1012c)1001d)1031Correct answer is option 'A'. Can you explain this answer?.
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