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A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn from the box. What is the probability that gems of all the three colours are chosen? (Answer up to three decimal places)
- a)- 0.95 sin 377t V
- b)0.95 sin 377t V
- c)- 0.95 cos 377t V
- d)0.95 cos 377t V
Correct answer is '0.545'. Can you explain this answer?
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Most Upvoted Answer
A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn fro...
Total number of gems = 4 + 3 + 5 = 12
∴ Total number of ways in which 4 gems can be chosen
∴ Total number of ways in which 4 gems can be chosen
Each coloured gem will be chosen in the following mutually exclusive ways:
∴ Number of ways of drawing four gems in the above manner
= 90 + 60 + 120 = 270
∴ Required probability = Favourable outcomes/Total number of outcomes = 270/495 = 6/11 = 0.545
∴ Required probability = Favourable outcomes/Total number of outcomes = 270/495 = 6/11 = 0.545
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Community Answer
A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn fro...
To find the probability of drawing gems of all three colors, we need to consider the total number of ways we can choose four gems from the box.
Total number of ways to choose four gems from the box = (Number of ways to choose 4 gems from 4 blue gems) * (Number of ways to choose 0 gems from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 3 gems from 4 blue gems) * (Number of ways to choose 1 gem from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 2 gems from 4 blue gems) * (Number of ways to choose 2 gems from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 1 gem from 4 blue gems) * (Number of ways to choose 3 gems from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 0 gems from 4 blue gems) * (Number of ways to choose 4 gems from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 3 gems from 4 blue gems) * (Number of ways to choose 1 gem from 3 green gems) * (Number of ways to choose 1 gem from 5 red gems) + (Number of ways to choose 2 gems from 4 blue gems) * (Number of ways to choose 2 gems from 3 green gems) * (Number of ways to choose 1 gem from 5 red gems) + (Number of ways to choose 1 gem from 4 blue gems) * (Number of ways to choose 3 gems from 3 green gems) * (Number of ways to choose 1 gem from 5 red gems) + (Number of ways to choose 0 gems from 4 blue gems) * (Number of ways to choose 4 gems from 3 green gems) * (Number of ways to choose 1 gem from 5 red gems) + (Number of ways to choose 3 gems from 4 blue gems) * (Number of ways to choose 1 gem from 3 green gems) * (Number of ways to choose 2 gems from 5 red gems) + (Number of ways to choose 2 gems from 4 blue gems) * (Number of ways to choose 2 gems from 3 green gems) * (Number of ways to choose 2 gems from 5 red gems) + (Number of ways to choose 1 gem from 4 blue gems) * (Number of ways to choose 3 gems from 3 green gems) * (Number of ways to choose 2 gems from 5 red gems) + (Number of ways to choose 0 gems from 4 blue gems) * (Number of ways to choose 4 gems from 3 green gems) * (Number of ways to choose 2 gems from 5 red gems) + (Number of ways to choose 3 gems from 4 blue gems) * (Number of ways to choose 1 gem from 3 green gems) * (Number
Total number of ways to choose four gems from the box = (Number of ways to choose 4 gems from 4 blue gems) * (Number of ways to choose 0 gems from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 3 gems from 4 blue gems) * (Number of ways to choose 1 gem from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 2 gems from 4 blue gems) * (Number of ways to choose 2 gems from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 1 gem from 4 blue gems) * (Number of ways to choose 3 gems from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 0 gems from 4 blue gems) * (Number of ways to choose 4 gems from 3 green gems) * (Number of ways to choose 0 gems from 5 red gems) + (Number of ways to choose 3 gems from 4 blue gems) * (Number of ways to choose 1 gem from 3 green gems) * (Number of ways to choose 1 gem from 5 red gems) + (Number of ways to choose 2 gems from 4 blue gems) * (Number of ways to choose 2 gems from 3 green gems) * (Number of ways to choose 1 gem from 5 red gems) + (Number of ways to choose 1 gem from 4 blue gems) * (Number of ways to choose 3 gems from 3 green gems) * (Number of ways to choose 1 gem from 5 red gems) + (Number of ways to choose 0 gems from 4 blue gems) * (Number of ways to choose 4 gems from 3 green gems) * (Number of ways to choose 1 gem from 5 red gems) + (Number of ways to choose 3 gems from 4 blue gems) * (Number of ways to choose 1 gem from 3 green gems) * (Number of ways to choose 2 gems from 5 red gems) + (Number of ways to choose 2 gems from 4 blue gems) * (Number of ways to choose 2 gems from 3 green gems) * (Number of ways to choose 2 gems from 5 red gems) + (Number of ways to choose 1 gem from 4 blue gems) * (Number of ways to choose 3 gems from 3 green gems) * (Number of ways to choose 2 gems from 5 red gems) + (Number of ways to choose 0 gems from 4 blue gems) * (Number of ways to choose 4 gems from 3 green gems) * (Number of ways to choose 2 gems from 5 red gems) + (Number of ways to choose 3 gems from 4 blue gems) * (Number of ways to choose 1 gem from 3 green gems) * (Number
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A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn from the box. What is the probability that gems of all the three colours are chosen? (Answer up to three decimal places)a)- 0.95 sin 377t Vb)0.95 sin 377t Vc)- 0.95 cos 377t Vd)0.95 cos 377t VCorrect answer is '0.545'. Can you explain this answer?
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A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn from the box. What is the probability that gems of all the three colours are chosen? (Answer up to three decimal places)a)- 0.95 sin 377t Vb)0.95 sin 377t Vc)- 0.95 cos 377t Vd)0.95 cos 377t VCorrect answer is '0.545'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn from the box. What is the probability that gems of all the three colours are chosen? (Answer up to three decimal places)a)- 0.95 sin 377t Vb)0.95 sin 377t Vc)- 0.95 cos 377t Vd)0.95 cos 377t VCorrect answer is '0.545'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn from the box. What is the probability that gems of all the three colours are chosen? (Answer up to three decimal places)a)- 0.95 sin 377t Vb)0.95 sin 377t Vc)- 0.95 cos 377t Vd)0.95 cos 377t VCorrect answer is '0.545'. Can you explain this answer?.
A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn from the box. What is the probability that gems of all the three colours are chosen? (Answer up to three decimal places)a)- 0.95 sin 377t Vb)0.95 sin 377t Vc)- 0.95 cos 377t Vd)0.95 cos 377t VCorrect answer is '0.545'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn from the box. What is the probability that gems of all the three colours are chosen? (Answer up to three decimal places)a)- 0.95 sin 377t Vb)0.95 sin 377t Vc)- 0.95 cos 377t Vd)0.95 cos 377t VCorrect answer is '0.545'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains 4 blue, 3 green and 5 red gems. Four gems are drawn from the box. What is the probability that gems of all the three colours are chosen? (Answer up to three decimal places)a)- 0.95 sin 377t Vb)0.95 sin 377t Vc)- 0.95 cos 377t Vd)0.95 cos 377t VCorrect answer is '0.545'. Can you explain this answer?.
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