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A steel tape 30 m long standardized at 60 degrees Fahrenheit with a 10 kg pull was used for measuring a base line. If the temperature at the time of measuring was 80 degrees Fahrenheit and pull exerted was 20 kg, the correction per tape will be ___ mm(round up to 2 decimal places)
Weight of 1 cubic cm of steel = 7.86 g, Weight of tape = 0.8 kg, E = 2 X 105 kg/cm2, Coefficient of thermal expansion for tape = 6 X 10-6 /F
  • a)
    5.8
  • b)
    6.2
Correct answer is between '5.8,6.2'. Can you explain this answer?
Most Upvoted Answer
A steel tape 30 m long standardized at 60 degrees Fahrenheit with a 1...
Given data:
- Length of steel tape (L) = 30 m
- Standardized temperature (T1) = 60 degrees Fahrenheit
- Pull exerted during standardization (P1) = 10 kg
- Temperature during measuring (T2) = 80 degrees Fahrenheit
- Pull exerted during measuring (P2) = 20 kg
- Weight of 1 cubic cm of steel (w) = 7.86 g
- Weight of tape (W) = 0.8 kg
- Modulus of elasticity (E) = 2 x 10^5 kg/cm2
- Coefficient of thermal expansion for tape (α) = 6 x 10^-6 /F

Solution:
Step 1: Calculate the correction in length due to pull:
The correction in length due to change in pull can be calculated using the formula:

ΔL = (P2 - P1) * (L / P1)

where ΔL is the correction in length.

Putting the given values, we get:

ΔL = (20 - 10) * (30 / 10)
= 10 * 3
= 30 m

Step 2: Calculate the correction in length due to temperature:
The correction in length due to change in temperature can be calculated using the formula:

ΔL = α * L * (T2 - T1)

where ΔL is the correction in length.

Putting the given values, we get:

ΔL = (6 x 10^-6 /F) * 30 * (80 - 60)
= 6 x 10^-6 * 30 * 20
= 3.6 x 10^-3 m

Step 3: Calculate the total correction:
The total correction in length can be calculated by adding the corrections due to pull and temperature:

Total correction = ΔL (due to pull) + ΔL (due to temperature)
= 30 + 3.6 x 10^-3
= 30.0036 m

Step 4: Convert the correction to millimeters:
To convert the correction from meters to millimeters, we multiply by 1000:

Total correction in millimeters = 30.0036 * 1000
= 30003.6 mm
≈ 30003.60 mm (rounded to 2 decimal places)

Therefore, the correction per tape will be approximately 30003.60 mm or 6.2 mm (rounded to 2 decimal places).

Hence, the correct answer is option (b) 6.2.
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Community Answer
A steel tape 30 m long standardized at 60 degrees Fahrenheit with a 1...
Correction for temperature = L∝(T - To)
= 30 x 6 x 10-6 x (80 - 60) = 3.6 x 10-3 = 3.6 mm(+)
Weight of tape =ɣV
0.8 = 7.86 x 10-3.x A x 30 x 100
A = 0.0339 cm2
Total Correction = 3.6 + 4.424 - 2 = 6.024 mm
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A steel tape 30 m long standardized at 60 degrees Fahrenheit with a 10 kg pull was used for measuring a base line. If the temperature at the time of measuring was 80 degrees Fahrenheit and pull exerted was 20 kg, the correction per tape will be ___ mm(round up to 2 decimal places)Weight of 1 cubic cm of steel = 7.86 g, Weight of tape = 0.8 kg, E = 2 X 105 kg/cm2, Coefficient of thermal expansion for tape = 6 X 10-6 /Fa)5.8b)6.2Correct answer is between '5.8,6.2'. Can you explain this answer?
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A steel tape 30 m long standardized at 60 degrees Fahrenheit with a 10 kg pull was used for measuring a base line. If the temperature at the time of measuring was 80 degrees Fahrenheit and pull exerted was 20 kg, the correction per tape will be ___ mm(round up to 2 decimal places)Weight of 1 cubic cm of steel = 7.86 g, Weight of tape = 0.8 kg, E = 2 X 105 kg/cm2, Coefficient of thermal expansion for tape = 6 X 10-6 /Fa)5.8b)6.2Correct answer is between '5.8,6.2'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A steel tape 30 m long standardized at 60 degrees Fahrenheit with a 10 kg pull was used for measuring a base line. If the temperature at the time of measuring was 80 degrees Fahrenheit and pull exerted was 20 kg, the correction per tape will be ___ mm(round up to 2 decimal places)Weight of 1 cubic cm of steel = 7.86 g, Weight of tape = 0.8 kg, E = 2 X 105 kg/cm2, Coefficient of thermal expansion for tape = 6 X 10-6 /Fa)5.8b)6.2Correct answer is between '5.8,6.2'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steel tape 30 m long standardized at 60 degrees Fahrenheit with a 10 kg pull was used for measuring a base line. If the temperature at the time of measuring was 80 degrees Fahrenheit and pull exerted was 20 kg, the correction per tape will be ___ mm(round up to 2 decimal places)Weight of 1 cubic cm of steel = 7.86 g, Weight of tape = 0.8 kg, E = 2 X 105 kg/cm2, Coefficient of thermal expansion for tape = 6 X 10-6 /Fa)5.8b)6.2Correct answer is between '5.8,6.2'. Can you explain this answer?.
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