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A surface grinding operation has the following data wheel speed = 22 m/s; Table speed = 0.18 m/s; Tangential force = 88 N; Depth of cut = 0.018 mm; Width of cut = 14 mm
The power required per mm3 of metal removed per second (in J/mm3) is______________ (Round off to two decimal places)
Correct answer is '42.68'. Can you explain this answer?
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A surface grinding operation has the following data wheel speed = 22 ...
Tangential force F = 88 N
Wheel speed V = 22 m/s
Power required P = F x V = 88 x 22 = 1936 W
Depth of cut d = 0.018 mm
Width of cut b = 14 mm
Work speed fm = 0.18 m/s = 180 mm/s
Volume of metal removed per sec W = d x b x fm
∴ W= 0.018 x 14 x 180 = 45.36 mm3
Power required / mm3 = P/W = 1936/45.36 = 42.68 J/mm3
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A surface grinding operation has the following data wheel speed = 22 ...
To calculate the power required per mm3 of metal removed per second, we can use the formula:
Power = (Tangential force * Table speed) / (Depth of cut * Width of cut)
Given data:
- Wheel speed = 22 m/s
- Table speed = 0.18 m/s
- Tangential force = 88 N
- Depth of cut = 0.018 mm
- Width of cut = 14 mm
Let's calculate the power required per mm3 of metal removed per second step by step:
1. Convert the depth of cut to meters:
Depth of cut = 0.018 mm = 0.018 * 10^-3 m = 1.8 * 10^-5 m
2. Calculate the volume of metal removed per second:
Volume = Depth of cut * Width of cut * Table speed
Volume = (1.8 * 10^-5 m) * (14 * 10^-3 m) * (0.18 m/s)
Volume = 0.00004536 m3/s
3. Calculate the power required:
Power = (Tangential force * Table speed) / (Depth of cut * Width of cut)
Power = (88 N) * (0.18 m/s) / (1.8 * 10^-5 m * 14 * 10^-3 m)
Power = 0.088 / (2.52 * 10^-7) = 349206.35 W
4. Convert the power to J/mm3:
Power = 349206.35 W = 349206.35 J/s
Power per mm3 = 349206.35 J/s / 0.00004536 m3/s
Power per mm3 = 7692307692.31 J/m3
5. Convert the power per mm3 to J/mm3 (rounding off to two decimal places):
Power per mm3 = 7692307692.31 J/m3 = 42.68 J/mm3
Therefore, the power required per mm3 of metal removed per second is 42.68 J/mm3.
Power = (Tangential force * Table speed) / (Depth of cut * Width of cut)
Given data:
- Wheel speed = 22 m/s
- Table speed = 0.18 m/s
- Tangential force = 88 N
- Depth of cut = 0.018 mm
- Width of cut = 14 mm
Let's calculate the power required per mm3 of metal removed per second step by step:
1. Convert the depth of cut to meters:
Depth of cut = 0.018 mm = 0.018 * 10^-3 m = 1.8 * 10^-5 m
2. Calculate the volume of metal removed per second:
Volume = Depth of cut * Width of cut * Table speed
Volume = (1.8 * 10^-5 m) * (14 * 10^-3 m) * (0.18 m/s)
Volume = 0.00004536 m3/s
3. Calculate the power required:
Power = (Tangential force * Table speed) / (Depth of cut * Width of cut)
Power = (88 N) * (0.18 m/s) / (1.8 * 10^-5 m * 14 * 10^-3 m)
Power = 0.088 / (2.52 * 10^-7) = 349206.35 W
4. Convert the power to J/mm3:
Power = 349206.35 W = 349206.35 J/s
Power per mm3 = 349206.35 J/s / 0.00004536 m3/s
Power per mm3 = 7692307692.31 J/m3
5. Convert the power per mm3 to J/mm3 (rounding off to two decimal places):
Power per mm3 = 7692307692.31 J/m3 = 42.68 J/mm3
Therefore, the power required per mm3 of metal removed per second is 42.68 J/mm3.
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A surface grinding operation has the following data wheel speed = 22 m/s; Table speed = 0.18 m/s; Tangential force = 88 N; Depth of cut = 0.018 mm; Width of cut = 14 mmThe power required per mm3 of metal removed per second (in J/mm3) is______________ (Round off to two decimal places)Correct answer is '42.68'. Can you explain this answer?
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A surface grinding operation has the following data wheel speed = 22 m/s; Table speed = 0.18 m/s; Tangential force = 88 N; Depth of cut = 0.018 mm; Width of cut = 14 mmThe power required per mm3 of metal removed per second (in J/mm3) is______________ (Round off to two decimal places)Correct answer is '42.68'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A surface grinding operation has the following data wheel speed = 22 m/s; Table speed = 0.18 m/s; Tangential force = 88 N; Depth of cut = 0.018 mm; Width of cut = 14 mmThe power required per mm3 of metal removed per second (in J/mm3) is______________ (Round off to two decimal places)Correct answer is '42.68'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A surface grinding operation has the following data wheel speed = 22 m/s; Table speed = 0.18 m/s; Tangential force = 88 N; Depth of cut = 0.018 mm; Width of cut = 14 mmThe power required per mm3 of metal removed per second (in J/mm3) is______________ (Round off to two decimal places)Correct answer is '42.68'. Can you explain this answer?.
A surface grinding operation has the following data wheel speed = 22 m/s; Table speed = 0.18 m/s; Tangential force = 88 N; Depth of cut = 0.018 mm; Width of cut = 14 mmThe power required per mm3 of metal removed per second (in J/mm3) is______________ (Round off to two decimal places)Correct answer is '42.68'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A surface grinding operation has the following data wheel speed = 22 m/s; Table speed = 0.18 m/s; Tangential force = 88 N; Depth of cut = 0.018 mm; Width of cut = 14 mmThe power required per mm3 of metal removed per second (in J/mm3) is______________ (Round off to two decimal places)Correct answer is '42.68'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A surface grinding operation has the following data wheel speed = 22 m/s; Table speed = 0.18 m/s; Tangential force = 88 N; Depth of cut = 0.018 mm; Width of cut = 14 mmThe power required per mm3 of metal removed per second (in J/mm3) is______________ (Round off to two decimal places)Correct answer is '42.68'. Can you explain this answer?.
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