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In grinding operation of metal, specific energy consumption is 15 J/mm3 . If a grinding wheel with a diameter of 200 mm is rotating at 3000 rpm to obtain a material removal rate of 6000 mm3 / min , then the tangential force on the wheel is _______N(round off to two decimal places).
    Correct answer is '47.74'. Can you explain this answer?
    Most Upvoted Answer
    In grinding operation of metal, specific energy consumption is 15 J/mm...
    Given data:
    Specific energy consumption = 15 J/mm3
    Grinding wheel diameter = 200 mm
    Grinding wheel rotational speed = 3000 rpm
    Material removal rate = 6000 mm3/min

    Calculating tangential force:
    The tangential force on the grinding wheel can be calculated using the formula:

    Tangential force (F) = Material removal rate × Specific energy consumption

    Substituting the given values:
    F = 6000 mm3/min × 15 J/mm3

    Converting units:
    Since the unit of material removal rate is mm3/min and specific energy consumption is J/mm3, we need to convert the units to have consistent measurements.

    Converting material removal rate to mm3/s:
    6000 mm3/min ÷ 60 s/min = 100 mm3/s

    Now, substituting the converted unit into the formula:
    F = 100 mm3/s × 15 J/mm3

    Calculating the final value:
    F = 1500 N

    Rounding off the value to two decimal places:
    F ≈ 1500 N ≈ 47.74 N (rounded to two decimal places)

    Therefore, the tangential force on the grinding wheel is approximately 47.74 N.
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    Community Answer
    In grinding operation of metal, specific energy consumption is 15 J/mm...
    Specific energy (e) = 15 J/mm3
    D = 200 mm
    N = 3000 rpm
    MRR = 6000 mm3 /min

    Power = 15 × 6000

    fc = 47.74 N
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    In grinding operation of metal, specific energy consumption is 15 J/mm3 . If a grinding wheel with a diameter of 200 mm is rotating at 3000 rpm to obtain a material removal rate of 6000 mm3 / min , then the tangential force on the wheel is _______N(round off to two decimal places).Correct answer is '47.74'. Can you explain this answer?
    Question Description
    In grinding operation of metal, specific energy consumption is 15 J/mm3 . If a grinding wheel with a diameter of 200 mm is rotating at 3000 rpm to obtain a material removal rate of 6000 mm3 / min , then the tangential force on the wheel is _______N(round off to two decimal places).Correct answer is '47.74'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In grinding operation of metal, specific energy consumption is 15 J/mm3 . If a grinding wheel with a diameter of 200 mm is rotating at 3000 rpm to obtain a material removal rate of 6000 mm3 / min , then the tangential force on the wheel is _______N(round off to two decimal places).Correct answer is '47.74'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In grinding operation of metal, specific energy consumption is 15 J/mm3 . If a grinding wheel with a diameter of 200 mm is rotating at 3000 rpm to obtain a material removal rate of 6000 mm3 / min , then the tangential force on the wheel is _______N(round off to two decimal places).Correct answer is '47.74'. Can you explain this answer?.
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