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A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).
Correct answer is between '38,39'. Can you explain this answer?
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Most Upvoted Answer
A surface grinding operation has been performed on a Cast Iron plate h...
Given:
Length = 300 mm, width = 10 mm, height = 50 mm, D = 150 mm, V = 40 m/sec, Table speed = 5 m/min =
Depth of cut = 50 μm = 50 × 10-3 mm = 0.050 mm, Fc = 40 N
Power = Fc × V = 40 × 40 = 1600 W
Material removal rate (MRR) = Table speed × width × depth of cut = 5000/60 × 10 × 0.05 = 41.666 mm3/sec =160041.666
The value of the specific grinding energy under the aforesaid grinding conditions is 38.4 J/mm3.
Length = 300 mm, width = 10 mm, height = 50 mm, D = 150 mm, V = 40 m/sec, Table speed = 5 m/min =
Depth of cut = 50 μm = 50 × 10-3 mm = 0.050 mm, Fc = 40 N
Power = Fc × V = 40 × 40 = 1600 W
Material removal rate (MRR) = Table speed × width × depth of cut = 5000/60 × 10 × 0.05 = 41.666 mm3/sec =160041.666
The value of the specific grinding energy under the aforesaid grinding conditions is 38.4 J/mm3.
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A surface grinding operation has been performed on a Cast Iron plate h...
X 200 mm (width) x 20 mm (thickness). The grinding wheel used had a diameter of 250 mm and rotated at a speed of 3000 rpm. The grinding depth was set at 0.1 mm. The feed rate of the grinding wheel was 1000 mm/min.
To calculate the time required for the grinding operation, we need to consider the length of travel of the grinding wheel across the surface of the cast iron plate.
The length of travel can be calculated using the formula:
Length of travel = Length of the plate - Diameter of the grinding wheel
Length of travel = 300 mm - 250 mm = 50 mm
Now, let's calculate the time required for the grinding operation.
Time = Length of travel / Feed rate
Time = 50 mm / 1000 mm/min
Time = 0.05 min (or 3 seconds)
Therefore, the time required for the grinding operation is 0.05 minutes (or 3 seconds).
To calculate the time required for the grinding operation, we need to consider the length of travel of the grinding wheel across the surface of the cast iron plate.
The length of travel can be calculated using the formula:
Length of travel = Length of the plate - Diameter of the grinding wheel
Length of travel = 300 mm - 250 mm = 50 mm
Now, let's calculate the time required for the grinding operation.
Time = Length of travel / Feed rate
Time = 50 mm / 1000 mm/min
Time = 0.05 min (or 3 seconds)
Therefore, the time required for the grinding operation is 0.05 minutes (or 3 seconds).
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A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer?
Question Description
A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer?.
A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer?.
Solutions for A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer?, a detailed solution for A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer? has been provided alongside types of A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A surface grinding operation has been performed on a Cast Iron plate having dimensions 300 mm (length) × 10 mm (width) × 50 mm (height). The grinding was performed using an alumina wheel having a wheel diameter of 150 mm and wheel width of 12 mm. The grinding velocity used is 40 m/s, table speed is 5 m/min, depth of cut per pass is 50μm and the number of grinding passes is 20. The average tangential and average normal forces for each pass are found to be 40 N and 60 N respectively. The value of the specific grinding energy under the aforesaid grinding condition is __________ J/mm3 (round off to one decimal place).Correct answer is between '38,39'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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