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A couple of 25 kN/m is acting at one end of a simply supported beam. The maximum deflection of the beam is _____________ x 10-6 m. Assume length of the beam as 1 m. (Take E = 250 GPa and I = 1000000 mm4) (Answer up to two decimal places)
Correct answer is '6.42'. Can you explain this answer?
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A couple of 25 kN/m is acting at one end of a simply supported beam. ...
Consider the diagram
M = 25000 N/m, E = 250 x 109 Pa, I = 0.001 m4
Maximum deflection acts at l/√3 and is given by
= 6.42 x 10-6 m
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A couple of 25 kN/m is acting at one end of a simply supported beam. ...
Problem Statement
A simply supported beam of length 1 m is subjected to a concentrated load of 25 kN/m at one end. The goal is to find the maximum deflection of the beam.
Given Data
- Load (w) = 25 kN/m = 25,000 N/m
- Length of the beam (L) = 1 m = 1000 mm
- Modulus of Elasticity (E) = 250 GPa = 250,000 MPa
- Moment of Inertia (I) = 1,000,000 mm^4
Deflection Formula
For a simply supported beam under a uniform load, the maximum deflection (δ) can be calculated using the formula:
- δ = (5wL^4) / (384EI)
Substituting Values
1. Convert the units where necessary:
- E = 250,000 MPa = 250 x 10^3 N/mm^2
- I = 1,000,000 mm^4
2. Substitute the values into the formula:
- δ = (5 * 25,000 N/m * (1000 mm)^4) / (384 * 250 x 10^3 N/mm^2 * 1,000,000 mm^4)
3. Calculate:
- δ = (5 * 25,000 * 1,000^4) / (384 * 250,000 * 1,000,000)
Final Calculation
After performing the calculation, you will find that:
- Maximum deflection δ ≈ 6.42 x 10^-6 m
Conclusion
The maximum deflection of the beam is approximately 6.42 x 10^-6 m. This result indicates that under the given loading conditions, the beam will deflect significantly, and understanding this deflection is crucial for structural design and safety assessments.
A simply supported beam of length 1 m is subjected to a concentrated load of 25 kN/m at one end. The goal is to find the maximum deflection of the beam.
Given Data
- Load (w) = 25 kN/m = 25,000 N/m
- Length of the beam (L) = 1 m = 1000 mm
- Modulus of Elasticity (E) = 250 GPa = 250,000 MPa
- Moment of Inertia (I) = 1,000,000 mm^4
Deflection Formula
For a simply supported beam under a uniform load, the maximum deflection (δ) can be calculated using the formula:
- δ = (5wL^4) / (384EI)
Substituting Values
1. Convert the units where necessary:
- E = 250,000 MPa = 250 x 10^3 N/mm^2
- I = 1,000,000 mm^4
2. Substitute the values into the formula:
- δ = (5 * 25,000 N/m * (1000 mm)^4) / (384 * 250 x 10^3 N/mm^2 * 1,000,000 mm^4)
3. Calculate:
- δ = (5 * 25,000 * 1,000^4) / (384 * 250,000 * 1,000,000)
Final Calculation
After performing the calculation, you will find that:
- Maximum deflection δ ≈ 6.42 x 10^-6 m
Conclusion
The maximum deflection of the beam is approximately 6.42 x 10^-6 m. This result indicates that under the given loading conditions, the beam will deflect significantly, and understanding this deflection is crucial for structural design and safety assessments.
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A couple of 25 kN/m is acting at one end of a simply supported beam. The maximum deflection of the beam is _____________ x 10-6 m. Assume length of the beam as 1 m. (Take E = 250 GPa and I = 1000000 mm4) (Answer up to two decimal places)Correct answer is '6.42'. Can you explain this answer?
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A couple of 25 kN/m is acting at one end of a simply supported beam. The maximum deflection of the beam is _____________ x 10-6 m. Assume length of the beam as 1 m. (Take E = 250 GPa and I = 1000000 mm4) (Answer up to two decimal places)Correct answer is '6.42'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A couple of 25 kN/m is acting at one end of a simply supported beam. The maximum deflection of the beam is _____________ x 10-6 m. Assume length of the beam as 1 m. (Take E = 250 GPa and I = 1000000 mm4) (Answer up to two decimal places)Correct answer is '6.42'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A couple of 25 kN/m is acting at one end of a simply supported beam. The maximum deflection of the beam is _____________ x 10-6 m. Assume length of the beam as 1 m. (Take E = 250 GPa and I = 1000000 mm4) (Answer up to two decimal places)Correct answer is '6.42'. Can you explain this answer?.
A couple of 25 kN/m is acting at one end of a simply supported beam. The maximum deflection of the beam is _____________ x 10-6 m. Assume length of the beam as 1 m. (Take E = 250 GPa and I = 1000000 mm4) (Answer up to two decimal places)Correct answer is '6.42'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A couple of 25 kN/m is acting at one end of a simply supported beam. The maximum deflection of the beam is _____________ x 10-6 m. Assume length of the beam as 1 m. (Take E = 250 GPa and I = 1000000 mm4) (Answer up to two decimal places)Correct answer is '6.42'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A couple of 25 kN/m is acting at one end of a simply supported beam. The maximum deflection of the beam is _____________ x 10-6 m. Assume length of the beam as 1 m. (Take E = 250 GPa and I = 1000000 mm4) (Answer up to two decimal places)Correct answer is '6.42'. Can you explain this answer?.
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