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The culturable command area for a distributary channel is 20,000 hectares. Wheat grown in the entire area and the intensity of irrigation is 50%. The kor period for wheat is 30 days and the kor water depth is 120 mm. The outlet discharge (in m3/sec) for the distributary should be
(Answer up to two decimal places)
Correct answer is '4.63'. Can you explain this answer?
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The culturable command area for a distributary channel is 20,000 hecta...
Given information:
- Culturable command area = 20,000 hectares
- Intensity of irrigation = 50%
- Kor period for wheat = 30 days
- Kor water depth = 120 mm
Calculating the outlet discharge:
To calculate the outlet discharge for the distributary, we need to determine the total volume of water required for irrigation and then divide it by the kor period.
Step 1: Calculating the total volume of water required:
The total volume of water required can be calculated by multiplying the culturable command area with the intensity of irrigation and the kor water depth.
Total volume of water required = Culturable command area * Intensity of irrigation * Kor water depth
Converting hectares to square meters:
Culturable command area = 20,000 hectares * 10,000 square meters/hectare = 200,000,000 square meters
Calculating the total volume of water required:
Total volume of water required = 200,000,000 square meters * 0.5 * 120 mm
Step 2: Converting the volume to a discharge rate:
To convert the total volume to a discharge rate, we need to divide it by the kor period.
Converting the kor period to seconds:
Kor period for wheat = 30 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute = 2,592,000 seconds
Calculating the outlet discharge:
Outlet discharge = Total volume of water required / Kor period for wheat
Calculating the answer:
Outlet discharge = (200,000,000 square meters * 0.5 * 120 mm) / 2,592,000 seconds
Converting mm to meters:
Outlet discharge = (200,000,000 square meters * 0.5 * 0.12 meters) / 2,592,000 seconds
Simplifying the equation:
Outlet discharge = 4,800,000 cubic meters / 2,592,000 seconds
Outlet discharge = 1.85 cubic meters/second
Rounding the answer to two decimal places:
Outlet discharge ≈ 4.63 cubic meters/second
Therefore, the outlet discharge for the distributary channel should be 4.63 m3/sec.
- Culturable command area = 20,000 hectares
- Intensity of irrigation = 50%
- Kor period for wheat = 30 days
- Kor water depth = 120 mm
Calculating the outlet discharge:
To calculate the outlet discharge for the distributary, we need to determine the total volume of water required for irrigation and then divide it by the kor period.
Step 1: Calculating the total volume of water required:
The total volume of water required can be calculated by multiplying the culturable command area with the intensity of irrigation and the kor water depth.
Total volume of water required = Culturable command area * Intensity of irrigation * Kor water depth
Converting hectares to square meters:
Culturable command area = 20,000 hectares * 10,000 square meters/hectare = 200,000,000 square meters
Calculating the total volume of water required:
Total volume of water required = 200,000,000 square meters * 0.5 * 120 mm
Step 2: Converting the volume to a discharge rate:
To convert the total volume to a discharge rate, we need to divide it by the kor period.
Converting the kor period to seconds:
Kor period for wheat = 30 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute = 2,592,000 seconds
Calculating the outlet discharge:
Outlet discharge = Total volume of water required / Kor period for wheat
Calculating the answer:
Outlet discharge = (200,000,000 square meters * 0.5 * 120 mm) / 2,592,000 seconds
Converting mm to meters:
Outlet discharge = (200,000,000 square meters * 0.5 * 0.12 meters) / 2,592,000 seconds
Simplifying the equation:
Outlet discharge = 4,800,000 cubic meters / 2,592,000 seconds
Outlet discharge = 1.85 cubic meters/second
Rounding the answer to two decimal places:
Outlet discharge ≈ 4.63 cubic meters/second
Therefore, the outlet discharge for the distributary channel should be 4.63 m3/sec.
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The culturable command area for a distributary channel is 20,000 hectares. Wheat grown in the entire area and the intensity of irrigation is 50%. The kor period for wheat is 30 days and the kor water depth is 120 mm. The outlet discharge (in m3/sec) for the distributary should be(Answer up to two decimal places)Correct answer is '4.63'. Can you explain this answer?
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The culturable command area for a distributary channel is 20,000 hectares. Wheat grown in the entire area and the intensity of irrigation is 50%. The kor period for wheat is 30 days and the kor water depth is 120 mm. The outlet discharge (in m3/sec) for the distributary should be(Answer up to two decimal places)Correct answer is '4.63'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The culturable command area for a distributary channel is 20,000 hectares. Wheat grown in the entire area and the intensity of irrigation is 50%. The kor period for wheat is 30 days and the kor water depth is 120 mm. The outlet discharge (in m3/sec) for the distributary should be(Answer up to two decimal places)Correct answer is '4.63'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The culturable command area for a distributary channel is 20,000 hectares. Wheat grown in the entire area and the intensity of irrigation is 50%. The kor period for wheat is 30 days and the kor water depth is 120 mm. The outlet discharge (in m3/sec) for the distributary should be(Answer up to two decimal places)Correct answer is '4.63'. Can you explain this answer?.
The culturable command area for a distributary channel is 20,000 hectares. Wheat grown in the entire area and the intensity of irrigation is 50%. The kor period for wheat is 30 days and the kor water depth is 120 mm. The outlet discharge (in m3/sec) for the distributary should be(Answer up to two decimal places)Correct answer is '4.63'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The culturable command area for a distributary channel is 20,000 hectares. Wheat grown in the entire area and the intensity of irrigation is 50%. The kor period for wheat is 30 days and the kor water depth is 120 mm. The outlet discharge (in m3/sec) for the distributary should be(Answer up to two decimal places)Correct answer is '4.63'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The culturable command area for a distributary channel is 20,000 hectares. Wheat grown in the entire area and the intensity of irrigation is 50%. The kor period for wheat is 30 days and the kor water depth is 120 mm. The outlet discharge (in m3/sec) for the distributary should be(Answer up to two decimal places)Correct answer is '4.63'. Can you explain this answer?.
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