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A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests that
  • a)
    the structure of the compound involves covalent bonding only.
  • b)
    the chlorine atoms must be in co-ordination sphere.
  • c)
    the van't Hoff factor of the compound would be unity.
  • d)
    on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.
Correct answer is option 'B,C'. Can you explain this answer?
Most Upvoted Answer
A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct e...
Since there are no ions involved in this compound, the Cl atoms are Coordinately bonded to Pd in the coordination sphere.
No precipitate of AgCl would be formed for chlorine atoms are non-ionisable.
For non-electrolytes, the value of van't Haff's factor is 1.
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A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer?
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A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer?.
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