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A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
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A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer?, a detailed solution for A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer? has been provided alongside types of A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A freshly prepared aqueous solution of Pd(NH3)2Cl2 does not conduct electricity. It suggests thata)the structure of the compound involves covalent bonding only.b)the chlorine atoms must be in co-ordination sphere.c)the van't Hoff factor of the compound would be unity.d)on adding excess of aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCl (s) would be obtained.Correct answer is option 'B,C'. Can you explain this answer? tests, examples and also practice JEE tests.