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Three resistances each of 4 Ω are connected to form a triangle. The resistance between any two terminals is
- a)12 Ω
- b)2 Ω
- c)6 Ω
- d)8/3 Ω
Correct answer is option 'D'. Can you explain this answer?
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Three resistances each of 4 Ω are connected to form a triangle. The r...
The two resistance are connected in series and the resultant is connected in parallel with the third resistance.
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Three resistances each of 4 Ω are connected to form a triangle. The r...
Analysis:
To find the equivalent resistance between any two terminals of the triangle, we can use the concept of series and parallel combinations of resistances.
Solution:
We are given three resistances, each of 4 Ω, connected to form a triangle. Let's label the three vertices of the triangle as A, B, and C.
Step 1: Analyzing the Triangle:
We can see that there are two resistances connected in series between points A and B. Let's label this equivalent resistance as R1.
Similarly, there are two resistances connected in series between points B and C. Let's label this equivalent resistance as R2.
Finally, there are two resistances connected in series between points C and A. Let's label this equivalent resistance as R3.
Step 2: Finding R1, R2, and R3:
When two resistances are connected in series, their equivalent resistance is the sum of their individual resistances. Therefore, the value of R1, R2, and R3 can be calculated as follows:
R1 = 4 Ω + 4 Ω = 8 Ω
R2 = 4 Ω + 4 Ω = 8 Ω
R3 = 4 Ω + 4 Ω = 8 Ω
Step 3: Finding the Equivalent Resistance:
Now, we can see that R1, R2, and R3 are connected in parallel between points A, B, and C.
When two resistances are connected in parallel, the reciprocal of their equivalent resistance is equal to the sum of the reciprocals of their individual resistances. Therefore, the value of the equivalent resistance, R, between any two terminals can be calculated as follows:
1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/8 Ω + 1/8 Ω + 1/8 Ω
1/R = 3/8 Ω
R = 8/3 Ω
Therefore, the correct answer is option 'D', 8/3 Ω.
To find the equivalent resistance between any two terminals of the triangle, we can use the concept of series and parallel combinations of resistances.
Solution:
We are given three resistances, each of 4 Ω, connected to form a triangle. Let's label the three vertices of the triangle as A, B, and C.
Step 1: Analyzing the Triangle:
We can see that there are two resistances connected in series between points A and B. Let's label this equivalent resistance as R1.
Similarly, there are two resistances connected in series between points B and C. Let's label this equivalent resistance as R2.
Finally, there are two resistances connected in series between points C and A. Let's label this equivalent resistance as R3.
Step 2: Finding R1, R2, and R3:
When two resistances are connected in series, their equivalent resistance is the sum of their individual resistances. Therefore, the value of R1, R2, and R3 can be calculated as follows:
R1 = 4 Ω + 4 Ω = 8 Ω
R2 = 4 Ω + 4 Ω = 8 Ω
R3 = 4 Ω + 4 Ω = 8 Ω
Step 3: Finding the Equivalent Resistance:
Now, we can see that R1, R2, and R3 are connected in parallel between points A, B, and C.
When two resistances are connected in parallel, the reciprocal of their equivalent resistance is equal to the sum of the reciprocals of their individual resistances. Therefore, the value of the equivalent resistance, R, between any two terminals can be calculated as follows:
1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/8 Ω + 1/8 Ω + 1/8 Ω
1/R = 3/8 Ω
R = 8/3 Ω
Therefore, the correct answer is option 'D', 8/3 Ω.
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Three resistances each of 4 Ω are connected to form a triangle. The resistance between any two terminals isa)12 Ωb)2 Ωc)6 Ωd)8/3 ΩCorrect answer is option 'D'. Can you explain this answer?
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Three resistances each of 4 Ω are connected to form a triangle. The resistance between any two terminals isa)12 Ωb)2 Ωc)6 Ωd)8/3 ΩCorrect answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Three resistances each of 4 Ω are connected to form a triangle. The resistance between any two terminals isa)12 Ωb)2 Ωc)6 Ωd)8/3 ΩCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three resistances each of 4 Ω are connected to form a triangle. The resistance between any two terminals isa)12 Ωb)2 Ωc)6 Ωd)8/3 ΩCorrect answer is option 'D'. Can you explain this answer?.
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