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Substation is supplying a load which consumes a complex power of 50+j50 MVA. A reactive power controlled capacitor bank is connected across load with a range of 0≤QC≤40MVAr . This QC controller adopts step wise control with each step of 5 MVAr. To improve overall power factor close to 0.9 lag, the number of steps connected will be________. (by considering step number ‘0’ for Qc = 0MVAr )
- a)5
- b)6
- c)7
- d)8
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Substation is supplying a load which consumes a complex power of 50+j5...
Understanding the Problem
The load consumes a complex power of 50 + j50 MVA, which means:
- Real Power (P) = 50 MW
- Reactive Power (Q) = 50 MVAr
The goal is to improve the power factor to approximately 0.9 lagging by using a capacitor bank that can supply reactive power (QC) in steps of 5 MVAr, with a maximum of 40 MVAr.
Calculating Initial Power Factor
To determine the initial power factor (PF):
- The apparent power (S) = √(P² + Q²) = √(50² + 50²) = √5000 = 70.71 MVA.
- Initial power factor (PF) = P / S = 50 / 70.71 = 0.707, which is lagging.
Desired Power Factor
To achieve a power factor of 0.9 lagging:
- Required P = 50 MW (remains the same)
- Desired apparent power (S') = P / PF = 50 / 0.9 = 55.56 MVA.
Calculating Required Reactive Power
To find the required reactive power (Q'):
- Q' = √(S'² - P²) = √(55.56² - 50²) = √(3092.45 - 2500) = √592.45 = 24.36 MVAr (approximately).
The required reactive power from the capacitor bank (QC) is:
- QC = Q - Q' = 50 - 24.36 = 25.64 MVAr.
Determining Number of Steps
Considering that each step of the capacitor bank can provide 5 MVAr:
- To achieve 25.64 MVAr, we round it to the nearest step, which is 25 MVAr.
- Number of steps = 25 MVAr / 5 MVAr per step = 5 steps.
Thus, the number of steps connected will be 5, confirming option 'A'.
The load consumes a complex power of 50 + j50 MVA, which means:
- Real Power (P) = 50 MW
- Reactive Power (Q) = 50 MVAr
The goal is to improve the power factor to approximately 0.9 lagging by using a capacitor bank that can supply reactive power (QC) in steps of 5 MVAr, with a maximum of 40 MVAr.
Calculating Initial Power Factor
To determine the initial power factor (PF):
- The apparent power (S) = √(P² + Q²) = √(50² + 50²) = √5000 = 70.71 MVA.
- Initial power factor (PF) = P / S = 50 / 70.71 = 0.707, which is lagging.
Desired Power Factor
To achieve a power factor of 0.9 lagging:
- Required P = 50 MW (remains the same)
- Desired apparent power (S') = P / PF = 50 / 0.9 = 55.56 MVA.
Calculating Required Reactive Power
To find the required reactive power (Q'):
- Q' = √(S'² - P²) = √(55.56² - 50²) = √(3092.45 - 2500) = √592.45 = 24.36 MVAr (approximately).
The required reactive power from the capacitor bank (QC) is:
- QC = Q - Q' = 50 - 24.36 = 25.64 MVAr.
Determining Number of Steps
Considering that each step of the capacitor bank can provide 5 MVAr:
- To achieve 25.64 MVAr, we round it to the nearest step, which is 25 MVAr.
- Number of steps = 25 MVAr / 5 MVAr per step = 5 steps.
Thus, the number of steps connected will be 5, confirming option 'A'.
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Community Answer
Substation is supplying a load which consumes a complex power of 50+j5...
Given
Complex power = 50 + j50MVA
Assume that C-bank injecting Qc amount of reactive power.
Let number of steps = n
So, Qc = 5nMVAr )
Now real and reactive power supplied by source Ps = 50MW
Qs = Q1-Qc = 50 - 5n
Overall power factor, 
It is given that
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Substation is supplying a load which consumes a complex power of 50+j50 MVA. A reactive power controlled capacitor bank is connected across load with a range of 0≤QC≤40MVAr . This QC controller adopts step wise control with each step of 5 MVAr. To improve overall power factor close to 0.9 lag, the number of steps connected will be________. (by considering step number ‘0’ for Qc = 0MVAr )a)5b)6c)7d)8Correct answer is option 'A'. Can you explain this answer?
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Substation is supplying a load which consumes a complex power of 50+j50 MVA. A reactive power controlled capacitor bank is connected across load with a range of 0≤QC≤40MVAr . This QC controller adopts step wise control with each step of 5 MVAr. To improve overall power factor close to 0.9 lag, the number of steps connected will be________. (by considering step number ‘0’ for Qc = 0MVAr )a)5b)6c)7d)8Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Substation is supplying a load which consumes a complex power of 50+j50 MVA. A reactive power controlled capacitor bank is connected across load with a range of 0≤QC≤40MVAr . This QC controller adopts step wise control with each step of 5 MVAr. To improve overall power factor close to 0.9 lag, the number of steps connected will be________. (by considering step number ‘0’ for Qc = 0MVAr )a)5b)6c)7d)8Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Substation is supplying a load which consumes a complex power of 50+j50 MVA. A reactive power controlled capacitor bank is connected across load with a range of 0≤QC≤40MVAr . This QC controller adopts step wise control with each step of 5 MVAr. To improve overall power factor close to 0.9 lag, the number of steps connected will be________. (by considering step number ‘0’ for Qc = 0MVAr )a)5b)6c)7d)8Correct answer is option 'A'. Can you explain this answer?.
Substation is supplying a load which consumes a complex power of 50+j50 MVA. A reactive power controlled capacitor bank is connected across load with a range of 0≤QC≤40MVAr . This QC controller adopts step wise control with each step of 5 MVAr. To improve overall power factor close to 0.9 lag, the number of steps connected will be________. (by considering step number ‘0’ for Qc = 0MVAr )a)5b)6c)7d)8Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Substation is supplying a load which consumes a complex power of 50+j50 MVA. A reactive power controlled capacitor bank is connected across load with a range of 0≤QC≤40MVAr . This QC controller adopts step wise control with each step of 5 MVAr. To improve overall power factor close to 0.9 lag, the number of steps connected will be________. (by considering step number ‘0’ for Qc = 0MVAr )a)5b)6c)7d)8Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Substation is supplying a load which consumes a complex power of 50+j50 MVA. A reactive power controlled capacitor bank is connected across load with a range of 0≤QC≤40MVAr . This QC controller adopts step wise control with each step of 5 MVAr. To improve overall power factor close to 0.9 lag, the number of steps connected will be________. (by considering step number ‘0’ for Qc = 0MVAr )a)5b)6c)7d)8Correct answer is option 'A'. Can you explain this answer?.
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