A discrete time signal g[n] is given asg[n] = u[n + 3] − u[n − 5]Sum ...
G[n] = u[n + 3] − u[n − 5]
∵ u[n+3] = 1, n ≥ -3
and y[n-5] = 1, n ≥ 5
g[n] consists of eight unit impulses from n = -3 to n = +4. Therefore, the sum of all values of g[n] is 8.
A discrete time signal g[n] is given asg[n] = u[n + 3] − u[n − 5]Sum ...
Discrete Time Signal g[n]
The given discrete time signal g[n] is defined as:
g[n] = u[n - 3] - u[n - 5]
Explanation
Let's break down the signal and analyze it step by step.
Step 1: Unit Step Function
The unit step function u[n] is defined as:
u[n] = 1, for n >= 0
u[n] = 0, for n < />
Step 2: g[n] = u[n - 3] - u[n - 5]
The signal g[n] is composed of two unit step functions, u[n - 3] and u[n - 5], with subtraction.
Step 3: Analysis of g[n]
Let's analyze the values of g[n] for different values of n.
For n < 0:="" />
Both u[n - 3] and u[n - 5] will be 0, as n - 3 < 0="" and="" n="" -="" 5="" />< 0.="" therefore,="" g[n]="" />
For 0 <= n="">=>< 3:="" />
u[n - 3] will be 0, as n - 3 < 0.="" however,="" u[n="" -="" 5]="" will="" be="" 1,="" as="" n="" -="" 5="" />= 0. Therefore, g[n] = 0 - 1 = -1.
For 3 <= n="">=>< 5:="" />
Both u[n - 3] and u[n - 5] will be 1, as n - 3 >= 0 and n - 5 >= 0. Therefore, g[n] = 1 - 1 = 0.
For 5 <= n:="">=>
Both u[n - 3] and u[n - 5] will be 1, as n - 3 >= 0 and n - 5 >= 0. Therefore, g[n] = 1 - 1 = 0.
Step 4: Sum of g[n]
To find the sum of all values of g[n], we need to sum over all possible values of n.
Sum of g[n] = g[0] + g[1] + g[2] + g[3] + g[4] + g[5] + ...
Substituting the values of g[n] for each range:
Sum of g[n] = 0 + 0 + 0 + 0 + 0 + 0 + ...
It is evident that the sum of all values of g[n] is 0.
Conclusion
The correct answer, as given, is '8'. However, based on the analysis of the signal g[n], the sum of all values of g[n] is 0. Therefore, there might be an error in the provided answer. It is recommended to double-check the given answer or seek clarification from the source.
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