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An elliptical cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Then
  • a)
    Electric field near A in the cavity = electric field near B in the cavity
  • b)
    Charge density at A = charge density at B
  • c)
    Potential at A = potential at B
  • d)
    Total electric field flux through the surface of the cavity is q/ε0
Correct answer is option 'C,D'. Can you explain this answer?
Most Upvoted Answer
An elliptical cavity is carved within a perfect conductor. A positive...
Under electrostatic condition, all points lying on the conductor are at same potential. Therefore, potential at A = potential at B. Hence, Option (potential at A = potential at B) is correct. From Gauss theorem, total flux through the surface of the cavity will be q/ε0.
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An elliptical cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Thena)Electric field near A in the cavity = electric field near B in the cavityb)Charge density at A = charge density at Bc)Potential at A = potential at Bd)Total electric field flux through the surface of the cavity is q/ε0Correct answer is option 'C,D'. Can you explain this answer?
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An elliptical cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Thena)Electric field near A in the cavity = electric field near B in the cavityb)Charge density at A = charge density at Bc)Potential at A = potential at Bd)Total electric field flux through the surface of the cavity is q/ε0Correct answer is option 'C,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An elliptical cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Thena)Electric field near A in the cavity = electric field near B in the cavityb)Charge density at A = charge density at Bc)Potential at A = potential at Bd)Total electric field flux through the surface of the cavity is q/ε0Correct answer is option 'C,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An elliptical cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Thena)Electric field near A in the cavity = electric field near B in the cavityb)Charge density at A = charge density at Bc)Potential at A = potential at Bd)Total electric field flux through the surface of the cavity is q/ε0Correct answer is option 'C,D'. Can you explain this answer?.
Solutions for An elliptical cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Thena)Electric field near A in the cavity = electric field near B in the cavityb)Charge density at A = charge density at Bc)Potential at A = potential at Bd)Total electric field flux through the surface of the cavity is q/ε0Correct answer is option 'C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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