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For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:
[Given: Molar mass of gas = 60 g/m,
    Correct answer is '2'. Can you explain this answer?
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    For real gases, the graph of PV v/s p at constant temperature is not ...
    For y-intercept
    (∵ The gas will behave like an ideal gas)
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    Sketch shows the plot of Z v/s P for of a hypothetical gas for one mole at three distinct temperature.Boyles temperature is the temperature at which a gas shows ideal behaviour over a pressure range in the low pressure region. Boyles temperature (T b) = a/Rb . If a plot is obtained at temperatures well below Boyles temperature then the curve will show negative deviation, in low pressure region and positive deviation in the high pressure region. Near critical temperature the curve is more likely as CO2 and the temperature well above critical temperature curve is more like H2 at 0C as shown above. At high pressure suppose all the constant temperature curve varies linearly with pressure according to the following equation:Q.As shown in the figure at 200 K and 500 atm value of compressibility factor is 2 (approx). Then volume of the gas at this point will be

    In the Figure, isotherms of CO2 at several temperatures near the critical point are shown. At the critical point (critical stat e), the distinction between the liquid and gaseous states disappear and the density of the gaseous substance is equal to that in the liquid state. For every gas this occurs at specific values of temperature and pressure, called critical temperature and critical pressure respectively. At temperatures and pressures above the critical point value, a gas is said be in a supercritical state. Critical constants are evaluated by solving the Vander W aals equation which is a cubic involume. The values are TcIn the supercritical region the behaviour is studied by plotting Z vs P plots. The variation in this region is studied with respect to boyles temperature aAt temperaturehigher than CB the variation is linear (Plot I) and at temperature lower than CB the variation is non linear (Plot II) With reference to the passage answers the following questions:Q.For a real gas at a given temperature, which of the following facts is not correct?

    In the Figure, isotherms of CO2 at several temperatures near the critical point are shown. At the critical point (critical stat e), the distinction between the liquid and gaseous states disappear and the density of the gaseous substance is equal to that in the liquid state. For every gas this occurs at specific values of temperature and pressure, called critical temperature and critical pressure respectively. At temperatures and pressures above the critical point value, a gas is said be in a supercritical state. Critical constants are evaluated by solving the Vander W aals equation which is a cubic involume. The values are TcIn the supercritical region the behaviour is studied by plotting Z vs P plots. The variation in this region is studied with respect to boyles temperature aAt temperaturehigher than CB the variation is linear (Plot I) and at temperature lower than CB the variation is non linear (Plot II) With reference to the passage answers the following questions:Q.The figure shows the effect of pressure on the compressibility factor, Z of a gas :The wrong conclusion(s) is/are

    In the Figure, isotherms of CO2 at several temperatures near the critical point are shown. At the critical point (critical stat e), the distinction between the liquid and gaseous states disappear and the density of the gaseous substance is equal to that in the liquid state. For every gas this occurs at specific values of temperature and pressure, called critical temperature and critical pressure respectively. At temperatures and pressures above the critical point value, a gas is said be in a supercritical state. Critical constants are evaluated by solving the Vander W aals equation which is a cubic involume. The values are TcIn the supercritical region the behaviour is studied by plotting Z vs P plots. The variation in this region is studied with respect to boyles temperature aAt temperaturehigher than CB the variation is linear (Plot I) and at temperature lower than CB the variation is non linear (Plot II) With reference to the passage answers the following questions:Q.In the figure representing variation of the compressibility fac tor z of a real gas with pressure

    Sketch shows the plot of Z v/s P for of a hypothetical gas for one mole at three distinct temperature.Boyles temperature is the temperature at which a gas shows ideal behaviour over a pressure range in the low pressure region. Boyles temperature (T b) = a/Rb . If a plot is obtained at temperatures well below Boyles temperature then the curve will show negative deviation, in low pressure region and positive deviation in the high pressure region. Near critical temperature the curve is more likely as CO2 and the temperature well above critical temperature curve is more like H2 at 0C as shown above. At high pressure suppose all the constant temperature curve varies linearly with pressure according to the following equation:Q.For 500 K plot value of Z changes from 2 to 2.2 if pressure is varied from 1000 atm to 1200 atm (high pressur e) then the value of b/RTwill be

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    For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer?
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    For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer?.
    Solutions for For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer?, a detailed solution for For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer? has been provided alongside types of For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice For real gases, the graph of PV v/s p at constant temperature is not linear. So, d/P or W/V.P will not be independent of P. (W→ Mass of gas, V → Volume, P → Pressure) y-intercept of the graph d/P (g/atm-L) v/s P (atm) at 360 K is:[Given: Molar mass of gas = 60 g/m, Correct answer is '2'. Can you explain this answer? tests, examples and also practice JEE tests.
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