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Illuminate the surface of a certain metal alternately with wave length λ1 = 0.35 μm and λ2 = 0.54 μm. It is found that the corresponding maximum velocity is of photo electron having a ratio n = 2. Find the work function of that metal (in eV).
(Round off up to 2 decimal places)
    Correct answer is '1.88'. Can you explain this answer?
    Most Upvoted Answer
    Illuminate the surface of a certain metal alternately with wave lengt...
    Using equation of two wave lengths,
    - W
    As, v1 = 2v2
    3W = 4
    3W =
    = 5.64 eV
    W =
    = 1.88 eV
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    Illuminate the surface of a certain metal alternately with wave length λ1 = 0.35 μm and λ2 = 0.54 μm. It is found that the corresponding maximum velocity is of photo electron having a ratio n = 2. Find the work function of that metal (in eV).(Round off up to 2 decimal places)Correct answer is '1.88'. Can you explain this answer?
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    Illuminate the surface of a certain metal alternately with wave length λ1 = 0.35 μm and λ2 = 0.54 μm. It is found that the corresponding maximum velocity is of photo electron having a ratio n = 2. Find the work function of that metal (in eV).(Round off up to 2 decimal places)Correct answer is '1.88'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Illuminate the surface of a certain metal alternately with wave length λ1 = 0.35 μm and λ2 = 0.54 μm. It is found that the corresponding maximum velocity is of photo electron having a ratio n = 2. Find the work function of that metal (in eV).(Round off up to 2 decimal places)Correct answer is '1.88'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Illuminate the surface of a certain metal alternately with wave length λ1 = 0.35 μm and λ2 = 0.54 μm. It is found that the corresponding maximum velocity is of photo electron having a ratio n = 2. Find the work function of that metal (in eV).(Round off up to 2 decimal places)Correct answer is '1.88'. Can you explain this answer?.
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